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1 year ago

What was the voltage on the battery for the #2 series circuit with two light bulbs?A: 4 VB: 18 VC: 4.5 VD: 9 V

1 answer:

8 0

We are given a series circuit with two light bulbs. In this case, the light bulbs act as resistors in series and the total resistance is:

$R_t=R_1+R_2$

That is the sum of all the resistances in series in the circuit. To determine the voltage we can use Ohm's law:

$V=IR$

Where "R" is the total resistance and "I" is the current in the circuit. Replacing we get:

$V=I(R_1+R_2)$

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3 years ago

a particle is moving along a circular path having a radius of 4 in such that its position as a function of time is given by thet

ANTONII [103]

Answer:

Explanation:

Given

radius of circular path $r=4\ in.$

Position is given by

$\theta =\cos 2t---1$

Differentiate 1 to angular velocity we get

$\frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega =-2\sin 2t----2$

Differentiate 2 to get angular acceleration

$\frac{\mathrm{d} \omega }{\mathrm{d} t}=-2^2\cos 2t ---3$

Net acceleration is the vector summation of tangential and centripetal force

$a_t=\alpha \times r$

$a_t=-4\cos 2t\times 4=-16\cos 2t$

$a_r=\omega ^2\cdot r$

$a_r=(-2\sin 2t)^2\cdot 4$

$a_r=16\sin^2(2t)$

$a_{net}=\sqrt{a_r^2+a_t^2}$

$a_{net}=\sqrt{(16\sin ^2(2t)+(-16\cos 2t)^2}$

$a_{net}=\sqrt{256\cos ^2(2t)+256\sin ^4(2t)}$

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3 years ago

Why would an atomic nucleus give off a particle?

zmey [24]

To make the nucleus more stable

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2 years ago

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What do we call the movement of electric charge?<br> A. Power B. Voltage C. Resistance D. Current

Alex Ar [27]

D. Current

Hope I helped!

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2 years ago

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What is her initial acceleration if she is initially stationary and wearing steel-bladed skates that point in the direction of?

madreJ [45]

We will apply the Newton's second Law so the we will be able to find the acceleration.
F (tot) = ma
a = F(tot) / m
a = 32.0 N / 65.0 kg = 0.492 m/s^2
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7 0

3 years ago