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1 year ago

What was the voltage on the battery for the #2 series circuit with two light bulbs?A: 4 VB: 18 VC: 4.5 VD: 9 V

1 answer:

8 0

We are given a series circuit with two light bulbs. In this case, the light bulbs act as resistors in series and the total resistance is:

$R_t=R_1+R_2$

That is the sum of all the resistances in series in the circuit. To determine the voltage we can use Ohm's law:

$V=IR$

Where "R" is the total resistance and "I" is the current in the circuit. Replacing we get:

$V=I(R_1+R_2)$

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A launched hopper reach to 1.20 m maximum height. How much is it’s launch velocity?

garri49 [273]

The launch velocity is 4.8 m/s

Explanation:

We can solve this problem by applying the law of conservation of energy. In fact, the mechanical energy of the hopper (equal to the sum of the potential energy + the kinetic energy) is conserved. So we can write:

$U_i +K_i = U_f + K_f$

where:

$U_i$ is the initial potential energy, at the bottom

$K_i$ is the initial kinetic energy, at the bottom

$U_f$ is the final potential energy, at the top

$K_f$ is the final kinetic energy, at the top

We can rewrite the equation as:

$mgh_i + \frac{1}{2}mu^2 = mgh_f + \frac{1}{2}mv^2$

where:

m is the mass of the hopper

$g=9.8 m/s^2$ is the acceleration of gravity

$h_i = 0$ is the initial height

u is the launch speed of the hopper

$h_f = 1.20 m$ is the maximum altitude reached by the hopper

v = 0 is the final speed (which is zero when the hopper reaches the maximum height)

Solving the equation for u, we find the launch speed of the hopper:

$u=\sqrt{2gh_g}=\sqrt{2(9.8)(1.20)}=4.8 m/s$

Learn more about kinetic energy and potential energy:

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#LearnwithBrainly

4 0

3 years ago

How many structures do prokaryotic cells have in common with the eukaryotic cells?

Feliz [49]

Two. The both have a plasma membrane and cytoplasm.

6 0

3 years ago

Read 2 more answers

For work to be accomplished we must have?

KiRa [710]

Answer:

a force and a movement in the same direction as the force.

Explanation:

4 0

4 years ago

If 500 cal of heat are added to a gas, and the gas expands doing 500 J of work on its surroundings, what is the change in the in

poizon [28]

Answer:

The change in the internal energy of the gas 1,595 J

Explanation:

The first law of thermodynamics establishes that in an isolated system energy is neither created nor destroyed, but undergoes transformations; If mechanical work is applied to a system, its internal energy varies; If the system is not isolated, part of the energy is transformed into heat that can leave or enter the system; and finally an isolated system is an adiabatic system (heat can neither enter nor exit, so no heat transfer takes place.)

This is summarized in the expression:

ΔU= Q - W

where the heat absorbed and the work done by the system on the environment are considered positive.

Taking these considerations into account, in this case:

Q= 500 cal= 2,092 J (being 1 cal=4.184 J)

W=500 J

Replacing:

ΔU= 2,092 J - 500 J

ΔU= 1,592 J whose closest answer is 1,595 J

<u><em>The change in the internal energy of the gas 1,595 J </em></u>

6 0

3 years ago

What to do with a brand new mobile phone battery

Rashid [163]

Place it in the back of your phone where the old battery was

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4 years ago