What was the voltage on the battery for the #2 series circuit with two light bulbs?A: 4 VB: 18 VC: 4.5 VD: 9 V

1 answer:

8 0

We are given a series circuit with two light bulbs. In this case, the light bulbs act as resistors in series and the total resistance is:

$R_t=R_1+R_2$

That is the sum of all the resistances in series in the circuit. To determine the voltage we can use Ohm's law:

$V=IR$

Where "R" is the total resistance and "I" is the current in the circuit. Replacing we get:

$V=I(R_1+R_2)$

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