Answer:
V=14.9 m/s
Explanation:
In order to solve this problem, we are going to use the formulas of parabolic motion.
The velocity X-component of the ball is given by:
The motion on the X axis is a constant velocity motion so:
The whole trajectory of the ball takes 1.48 seconds
We know that:
Knowing the X and Y components of the velocity, we can calculate its magnitude by:
Answer:
1/6 del peso en la tierra.
Answer:
Distance covered is equal to all the distance traveled.
So for example, if you go from A to B, and then from B to C, the total distance covered is AB + BC.
Displacement is equal to the difference between the final position and the initial position.
So if we go from A to B, the displacement is simply the line AB.
While if we go from A to B, and then from B to C, the displacement will be a segment that directly connects A and C, such that:
displacement = √( (AB)^2 + (BC)^2)
Now, if we want to find the points such that the magnitude of the distance covered is equal to the magnitude of the displacement, we need to look at the pairs that are directly connected by a straight line.
Those are:
A to B ( or B to A)
B to C (or C to B)
C to D (or D to C)
Answer:
QC = 122 KJ
QH = 2.64 x 122 = 322 KJ
Explanation:
TH = 500 Degree C = 500 + 273 = 773 K
TC = 20 degree C = 20 + 273 = 293 K
W cycle = 200 KJ
Use the formula for the work done in a cycle
Wcycle = QH - QC
200 = QH - QC ..... (1)
Usse
TH / TC = QH / QC
773 / 293 = QH / QC
QH / QC = 2.64
QH = 2.64 QC Put it in equation (1)
200 = 2.64 QC - QC
QC = 122 KJ
So, QH = 2.64 x 122 = 322 KJ
They would have disliked that they had to relearn how to measure.
