Question

A spherical shell contains three charged objects. The first and second objects have a charge of − 14.0 nC and 33.0 nC , respectively. The total electric flux through the shell is − 953 N ⋅ m 2 / C . What is the charge on the third object?

Answer 1

Explanation:

Formula depicting relation between total flux and total charge Q is as follows.

              $\phi = \frac{Q}{\epsilon_{o}}$    (Gauss's Law)

Putting the given values into the above formula as follows.

            Q = $\phi \times \epsilon_{o}$

                = $-953 Nm^{2}/C \times 8.854 \times 10^{-12}$

                = $-8.4 \times 10^{-9} C$

                = -8.4 nC

Therefore, when the unknown charge is q  then,

         -14.0 nC + 33.0 nC + q = -8.4 nC

               q = -27.4 nC

Thus, we can conclude that charge on the third object is -27.4 nC.