Step-by-step explanation:
X^a times X^b = X^a + b
so 4x times 6x = 24x^(1+1)
The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
Answer:
1.25 seconds
Step-by-step explanation:
Cosine is a maximum at cos(0) = 1, and a minimum at cos(π) = -1.
At the maximum:
8π/5 t = 0
t = 0
At the minimum:
8π/5 t = π
t = 5/8
t = 0.625
The time from maximum to minimum is 0.625 seconds. Therefore, the time from minimum back to maximum is also 0.625 seconds. So the total time is:
0.625 + 0.625 = 1.25
Divide both sides by f then cancel out
X= 7 I already solve it before check other questions.
