<span>Simplifying
4x + 20 = 6x + -10
Reorder the terms:
20 + 4x = 6x + -10
Reorder the terms:
20 + 4x = -10 + 6x
Solving
20 + 4x = -10 + 6x
Move all terms containing x to the left, all other terms to the right.
Add '-6x' to each side of the equation.
20 + 4x + -6x = -10 + 6x + -6x
Combine like terms: 4x + -6x = -2x
20 + -2x = -10 + 6x + -6x
Combine like terms: 6x + -6x = 0
20 + -2x = -10 + 0
20 + -2x = -10
Add '-20' to each side of the equation.
20 + -20 + -2x = -10 + -20
Combine like terms: 20 + -20 = 0
0 + -2x = -10 + -20
-2x = -10 + -20
Combine like terms: -10 + -20 = -30
-2x = -30
Divide each side by '-2'.
x = 15
Simplifying
x = 15</span>
Answer:
20
Step-by-step explanation:
This sequence follows a pattern of doubling then subtracting by two. The last action was 12 to 10, which is subtracting by two, so the next must be multiplying by 2.
Answer:
F, 3^4+x
Step-by-step explanation:
You just have to add the powers together but not the actual base, you keep it as it is
Answer:
(x, y) ⇒ (-x, y)
Step-by-step explanation:
When you're looking for a rule that transforms one figure to the other, the first step is to look at the figures. You want to identify their orientation (order of vertices) and the relative locations of corresponding vertices.
Here, vertices VWX are in <em>clockwise</em> order. The corresponding vertices V'W'X' are in <em>counterclockwise</em> order. For that to happen, there must be a reflection involved.
The y-axis goes through the midpoints of VV', WW' and XX'. This means the y-axis is the line of reflection. The coordinates of V'W'X' have the same y-values as their originals, but their x-values have changed sign.
The algebraic rule for these two figures is ...
(x, y) ⇒ (-x, y) . . . . . . reflection over y-axis; sign of x changes
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<em>Additional comment</em>
No rotation is involved here.
The rule (x, y) ⇒ (x, y+10) means the y-coordinate has had 10 added to it. That causes a translation upward by 10 units. This <em>is</em> the algebraic rule.
Answer:
If m is nonnegative (ie not allowed to be negative), then the answer is m^3
If m is allowed to be negative, then the answer is either |m^3| or |m|^3
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Explanation:
There are two ways to get this answer. The quickest is to simply divide the exponent 6 by 2 to get 6/2 = 3. This value of 3 is the final exponent over the base m. Why do we divide by 2? Because the square root is the same as having an exponent of 1/2 = 0.5, so
sqrt(m^6) = (m^6)^(1/2) = m^(6*1/2) = m^(6/2) = m^3
This assumes that m is nonnegative.
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A slightly longer method is to break up the square root into factors of m^2 each and then apply the rule that sqrt(x^2) = x, where x is nonnegative
sqrt(m^6) = sqrt(m^2*m^2*m^2)
sqrt(m^6) = sqrt(m^2)*sqrt(m^2)*sqrt(m^2)
sqrt(m^6) = m*m*m
sqrt(m^6) = m^3
where m is nonnegative
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If we allow m to be negative, then the final result would be either |m^3| or |m|^3.
The reason for the absolute value is to ensure that the expression m^3 is nonnegative. Keep in mind that m^6 is always nonnegative, so sqrt(m^6) is also always nonnegative. In order for sqrt(m^6) = m^3 to be true, the right side must be nonnegative.
Example: Let's say m = -2
m^6 = (-2)^6 = 64
sqrt(m^6) = sqrt(64) = 8
m^3 = (-2)^3 = -8
Without the absolute value, sqrt(m^6) = m^3 is false when m = -2
