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SVEN [57.7K]
3 years ago
7

Consider the following reaction at equilibrium: 2NH3 (g) N2 (g) + 3H2 (g) Le Châtelier's principle predicts that the moles of H2

in the reaction container will increase with ________. Consider the following reaction at equilibrium: 2NH3 (g) N2 (g) + 3H2 (g) Le Châtelier's principle predicts that the moles of in the reaction container will increase with ________. an increase in total pressure by the addition of helium gas (V and T constant) a decrease in the total pressure (T constant) some removal of NH3 from the reaction vessel (V and T constant) addition of some N2 to the reaction vessel (V and T constant) a decrease in the total volume of the reaction vessel (T constant)
Chemistry
1 answer:
Lilit [14]3 years ago
3 0

Answer:

A decrease in the total volume of the reaction vessel (T constant)

Explanation:

  • Le Châtelier's principle predicts that the moles of H2 in the reaction container will increase with a decrease in the total volume of the reaction vessel.
  • <em><u>According to the Le Chatelier's principle, when a chnage is a applied to a system at equilibrium, then the equilibrium will shift in a way that counteracts the effect causing it.</u></em>
  • In this case, a decrease in volume means there is an increase in pressure, therefore the equilibrium will shift towards the side with the fewer number of moles of gas.
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Hard water often contains dissolved Ca2+ and Mg2+ ions. One way to soften water is to add phosphates. The phosphate ion forms in
avanturin [10]
<span>5.5×10−2M in calcium chloride and 8.0×10−2M in magnesium nitrate.
What mass of sodium phosphate must be added to 1.5L of this solution to completely eliminate the hard water ion

1) Content of Ca (2+) ions

Calcium chloride = CaCl2

Ionization equation: CaCl2 ---> Ca (2+) + 2 Cl (-)

=> Molar ratios: 1 mol of CaCl2 : 1 mol Ca(2+) : 2 mol Cl(-)

Calculate the number of moles of CaCl2 in 1.5 liters of 5.5 * 10^-2 M solution

M = n / V => n = M*V = 5.5 * 10^ -2 M * 1.5 l = 0.0825 mol CaCl2

=> 0.0825 mol Ca(2+)

2) Number of phosphate ions needed to react with 0.0825 mol Ca(2+)

formula of phospahte ion: PO4 (3-)

molar ratio: 2PO4(3-) + 3Ca(2+) = Ca3 (PO4)2

Proportion: 2 mol PO4(3-) / 3 mol Ca(2+) = x / 0.0825 mol Ca(2+)

=> x = 0.0825 coml Ca(2+) * 2 mol PO4(3-) / 3 mol Ca(2+) = 0.055 mol PO4(3-)

3) Content of Mg(2+) ions

Ionization equation: Mg (NO3)2 ----> Mg(2+) + 2 NO3 (-)

Molar ratios: 1 mol Mg(NO3)2 : 1 mol Mg(2+) + 2 mol NO3(-)

number of moles of Mg(NO3)2 in 1.5 liter of 8.0 * 10^-2 M solution

n = M * V = 8.0 * 10^ -2 M * 1.5 liter = 0.12 moles Mg(NO3)2

ions of Mg(2+) = 0.12 mol Mg(NO3)2 * 1 mol Mg(2+) / mol Mg(NO3)2 = 0.12 mol Mg(2+)

4) Number of phosphate ions needed to react with 0.12 mol Mg(2+)

2PO4(3-) + 3Mg(2+) = Mg3(PO4)2

=> 2 mol PO4(3-) / 3 mol Mg(2+) = x / 0.12 mol Mg(2+)

=> x = 0.12 * 2/3 mol PO4(3-) = 0.16 mol PO4(3-)

5) Total number of moles of PO4(3-)

0.055 mol + 0.16 mol = 0.215 mol

6) Sodium phosphate

Sodium phosphate = Na3(PO4)

Na3PO4 ---> 3Na(+) + PO4(3-)

=> 1 mol Na3PO4 : 1 mol PO4(3-)

=> 0.215 mol PO4(3-) : 0.215 mol Na3PO4

mass in grams = number of moles * molar mass

molar mass of Na3 PO4 = 3*23 g/mol + 31 g/mol + 4*16 g/mol = 164 g/mol

=> mass in grams = 0.215 mol * 164 g/mol = 35.26 g

Answer: 35.26 g of sodium phosphate
</span>
5 0
3 years ago
Why would an atom become an ion?
crimeas [40]

Answer:

c

Explanation: correct me if im wrong

5 0
3 years ago
Please explain how roasting a hot dog over a fire involves all three forms of heat transfer. Please use full sentences and corre
sergejj [24]

Ok so First of all we start with the fire. The fire gives off radiation because you can feel the heat through space. The fire also gives of conduction because you put the hotdog on the fire to cook it, and the hotdog will give off steam when it is hot causing it to give of Convection.

There is how cooking a hotdog over a fire uses all three heat transfer

3 0
3 years ago
Calcuate the number of<br> grams of solute in 453.9mL<br> of 0.237 M calcium acetate
AysviL [449]

The number of  grams : 17.082 g

<h3>Further explanation</h3>

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

453.9 mL  of 0.237 M calcium acetate

  • mol

\tt mol=M\times V=0.237\times 0.4539=0.108

  • mass

MW Ca(C₂H₃OO)₂ : 158,17 g/mol

\tt mass=mol\times MW\\\\mass=0.108\times 158.17=17.082~g

4 0
3 years ago
What mass of cucl2 is contained in 75.85 g of a 22.4% by mass solution of cucl2 in water?
Sindrei [870]
First  step: convert   22.4%  into   fraction
 that  is  22.4/100  which  is equivalent  to 0.224
  The  mass  of Cucl2  contained  in  75.85  of  22.4%  by  mass  of   solution  of  CUcl2 in  water is   therefore,
0.224 x75.85=16.99g
alternatively
75.85 --->100%
      ?        22.4%
by cross  multiplication =(22.4 x 75.85)/100 =16.99g
5 0
3 years ago
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