According to Beer-<span>Lambert law the absorption of light by a solution is directly proportional to the concentration of that solution.
Mathmatically,
A = </span>∈ C l ------- (1)
Where,
A = Absorption = 1.23
∈ = molar absorptivity coefficient = 6460 M⁻¹cm⁻¹<span>
C = Concentration = ?
l = Path Length = 1 cm
Solving eq.1 for concentration,
C = A / </span>∈ l
Putting values,
C = 1.23 / (6460 M⁻¹cm⁻¹ × 1 cm)
C = 0.00019 mol/L
Answer:
1-butene
Explanation:
In this case, the problem is already stating and saying the reaction involved here.
1-bromobutane undergoes a dehydrohalogenation in presence of a base. This will cause an elimination reaction forming a product.
As this is an elimination product, this can be done in two ways.
The first way is with an unimolecular reaction where the halide is eliminated from the starting reactant in a two step reaction involving a carbocation formation. This is known as E1 reaction. However, the conditions for this reaction is to be in acid medium.
The second way is with a bimolecular reaction where the halide is eliminated from the starting reactant in just one step, and no carbocation is formed. This is known as E2 reaction and is commonly used with bases.
In the case of this problem, we are undergoing an E2 reaction, therefore, the mechanism of reaction is just one step, and when this happens, the base substract the hydrogen from Carbon 2, eliminates the bromide and forms a double bond, giving the 1-butene.
You can see the mechanism in the following picture.
Hope this helps
Yes it is a pure substance
Answer:
Since we can't utilize charges to make sense of what number of every particle we have (as we did with ionic mixes), we need to determine with prefixes mono-, di-, tri-, tetra, penta-, hexa-,, etc.
Answer:
<h2>50 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula

From the question we have

We have the final answer as
<h3>50 g/mL</h3>
Hope this helps you