Answer:
Explanation:
2 H₂S(g) +S0₂(g) = 3 S(s) + 2H₂0(g)
2 x 34 g 64 g 3 x 32 g
68 g of H₂S reacts with 64 g of S0₂
3.89 g of H₂S reacts with 64 x 3 .89 / 68 g of S0₂
3.89 g of H₂S reacts with 3.66 g of S0₂
S0₂ given is 4.11 g , so it is in excess .
Hence H₂S is limiting reagent .
68 g of H₂S reacts with S0₂ to give 96 g of Sulphur
3.89 g of H₂S reacts with S0₂ to give 96 x 3.89 / 68 g of Sulphur
3.89 g of H₂S reacts with S0₂ to give 96 x 3.89 / 68 g of Sulphur
5.49 g of Sulphur is produced .
Actual yield is 4.89
percentage yield = 4.89 x 100 / 5.49
= 89 % .
Answer:
12
Explanation:
23-11, why?, because, the difference between atomic and mass number is the neutron number which most a times is equivalent to the electron number.
Mass percentage of sodium chloride(NaCl) in ocean waters = 3.5 %
That means 3.5 g sodium chloride(NaCl) is present for every 100 g of ocean water.
The given mass of sodium chloride(NaCl) is 45.8 g
Calculating the mass of ocean waters that would contain 45.8 g sodium chloride(NaCl):
= 1309 g ocean water
Therefore, 45.8 g sodium chloride is present in 1309 g ocean water.
Answer:
C. CH₄ is less than NH₃ because the NH bond is more polar than the CH bond
Explanation:
The intermolecular forces between ammonia is far stronger than for methane. Between the molecules of ammonia we have the presence of hydrogen bonds. This bond is absent in methane.
Hydrogen bonds are one of the strongest intermolecular forces. It is as a result of the electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom N, O and F of another molecule.
- This strong interaction is absent in methane which has just dipole - dipole attraction.
The strength of the hydrogen bond depends on the electronegativity of the combining atoms.
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