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4 years ago

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Assessment timer and count Assessment items Item 3 What condition would most likely cause a decrease in the salinity of ocean wa

ter? freezing of glaciers extremely hot weather high rates of evaporation a river flowing into the sea

1 answer:

Goryan [66]4 years ago

3 0

Answer:

it's a river flowing into the sea

Explanation:

i had it on a quiz for k12 on god it's the good one have a good day

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Vladimir [108]

Answer:

A. (i think)

Explanation:

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3 years ago

During a volcanic eruption, lava flows at a rate of 26m/min. At this rate how far in kilometers can lava travel in 37 minutes?

MAXImum [283]

Answer:

Like stratovolcanoes, they can produce violent, explosive eruptions, but their lava generally does not flow far from the originating vent. Cryptodomes The 1980 eruption of Mount St. Helens was an example; lava beneath the surface of the mountain created an upward bulge which slid down the north side of the mountain.

Explanation:

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4 years ago

With a 0.5 M solution: How many moles of NaCl would there be in 1,000 ml?

Shalnov [3]

0.5 moles, though not a verified answer hope it helps! :D

5 0

3 years ago

Read 2 more answers

Which solution has the lowest freezing point?

elena55 [62]

The solution of Ba(OH)2 will have the lowest freezing point. This is because it dissociates into 3 ions, one Ba and 2 OH, which is more than any of the others. Freezing point depression is a colligitive property of water that depends, in part, on the number of ions.

hope it helps

5 0

3 years ago

Copper was the first metal to be produced from its ore because it is the easiest to smelt, that is, to refine by heating in the

Ganezh [65]

Answer:

57.48%

Explanation:

Calculate the mass of 1 mole of malachite:

MM Cu = 63.55

MM O = 16.00

MM H = 1.01

MM C = 12.01

$(Cu_{2}(OH)_{2}CO_{3})$

A mole of malachite has:

2 moles of Cu

5 moles of O

2 moles of H

1 mole of C

MW Malachite = 2*MM(CU) + 5*MM(O) + 2*MM(H) + 1 *MM(C)

MW Malachite = 2*63.55 + 5*16.00 + 2*1.01 + 1*12.01

MW Malachite = 221.13

Mass of Cu in a mole of Malachite = 2*MM(CU) = 127.1

Now divide the mass of Cu by the mass of Malachite

$%Cu = \frac{127.1}{221.13} =0.5748=57.48%$

7 0

4 years ago