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3 years ago

10th term of an= 20-2n

Mathematics

1 answer:

Dmitry [639]3 years ago

8 0

Answer:

We have that $a_{n} = 20-2n$

Step-by-step explanation:

We have just to replace n=10 on the general equation

$a_{10} = 20-2×10$

Therefore:

$a_{10} = 0$

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1. Find 3 equivalent fraction for the following: a) 5/6 b) 7/11 c) 9/7

SOVA2 [1]

Answer:

Step-by-step explanation:

To find equivalent fractions, multiply the numerator and the denominator by the same table.

a) 5/6

$\frac{5*2}{6*2}=\frac{10}{12}\\\\\frac{5*3}{6*3}=\frac{15}{18}\\\\\frac{5*4}{6*4}=\frac{20}{24}$

b) 7/11

$\frac{7*3}{11*3}=\frac{21}{33}\\\\\frac{7*4}{11*4}=\frac{28}{44}\\\\\frac{7*5}{11*5}=\frac{35}{55}$

c)9/7

$\frac{9*2}{7*2}=\frac{18}{14}\\\\\frac{9*5}{7*5}=\frac{45}{35}\\\\\frac{9*10}{7*10}=\frac{90}{70}$

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3 years ago

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Answer:

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3 years ago

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What are the x and y intercepts of this problem y=-3/8x-9

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Answer:

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Step-by-step explanation:

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3 years ago

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A spring has natural length 24 cm. Compare the work W1 done in stretching the spring from 24 cm to 34 cm with the work W2 done i

Scilla [17]

Answer:

From the analysis W1=W2.

they are directly related

Step-by-step explanation:

the work-done in stretching a spring can be expressed as

$W=\frac{1}{2}kx^2$

where k= spring constant

x= change on length of spring

Hence for W1

Given data

x= 34-24= 10 cm

solving in terms of k we have

$W=\frac{1}{2}k*10^2\\\W=\frac{1}{2}k*100\\\W=50k$

Hence for W2

Given data

x= 44-34= 10 cm

solving in terms of k we have

$W=\frac{1}{2}k*10^2\\\ W=\frac{1}{2}k*100\\\ W=50k$

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3 years ago