3. Use the chart to answer the following question. Amanda found a stone

Hoochie [10]

This problem uses the relationship between Ka and the concentrations of the ions. Calculations are as follows:

1.9 x 10-5= x^2 / (0.25 - x)

x is very small and the denominator is approximately equal to 0.25. Thus, x is 2.2 x 10^-3

pH = -log (2.2 x 10^-3) = 2.66

7 0

3 years ago

Fill in the blank in order to complete the path for pollen as it fertilizes a plant:anther → stigma --> style → _____________

jek_recluse [69]

The path taken by pollen as it fertilizes a plant would be:

anther ---> stigma ---> style ---> ovule

The fertilization process in plant starts by pollination. Pollen grains move from the anther of a flower to the stigma of the same or different flower. On the stigma, the pollen germinates and the cells of the pollen tube grows through the style to reach the ovule.

The generative cell of the pollen travel through the pollen tube to reach the embryo sac of the ovule. The cell divides by mitosis to form sperm cells and one of the sperm cells fertilizes the egg cell to form the zygote.

More on pollination can be found here: brainly.com/question/10482635

5 0

2 years ago

Why is sublimation such a critical component for the water cycle in cold climates?

Bumek [7]

The air is so dry that when it hits a snowpack, the frozen water evaporates, going directly from the ice to vapor and bypassing the liquid phase entirely. This is called sublimation, and it's a common way for snow to disappear in the arid West."

5 0

3 years ago

Read 2 more answers

How does the energy of independent atoms compare the energy of bonded atoms

Aleksandr [31]

Independent atoms have high potential energy,and they are highly unstable.

And when they form bonds their potential energy decreases and they become stable.

Hence bonded atoms are stable and have relatively low potential energy than independent atoms.

4 0

3 years ago

An acid solution is 0.100 M in HCl and 0.210 M in H2SO4. What volume of a 0.150 M solution of KOH must be added to 500.0 mL of t

Dmitry_Shevchenko [17]

Answer:

When we add 0.33L of KOH only the HCl solution will be neutralized. When we add 1.4 L of KOH, all of the acid (the HCl and H2SO4 solution) will be neutralized.

Explanation:

Step 1: Data given

The solution has 0.100 M HCl and 0.210 M H2SO4

Molarity KOH = 0.150 M

Volume of acid solution = 500 mL = 0.5 L

Step 2: Calculate moles of HCl

Moles HCl = Molarity HCl * volume

Moles HCl = 0.100 M * 0.5 L

Moles HCl = 0.05 moles

Step 3: Calculate moles of H2SO4

Moles H2SO4 = 0.210 M * 0.5 L

Moles H2SO4 = 0.105 moles

Step 4: The balanced neutralization reaction of KOH with HCl can be written as:

KOH + HCl → KCl + H2O

The mole ratio is 1:1

This means to neutralize 0.05 moles HCl, we need 0.05 moles KOH

Step 5: The balanced neutralization reaction of KOH with H2SO4 can be written as:

2KOH + H2SO4 → K2SO4 + 2H2O

The mole ratio KOH: H2SO4 is 2:1

This means to neutralize 0.105 moles H2SO4 we need 0.210 moles KOH

Step 6: Calculate volume of KOH needed to neutralize the solution

To neutralize the HCl solution: 0.05 moles / 0.150 M = 0.33 L KOH needed

To neutralize the H2SO4 solution: 0.210 moles / 0.150 M = 1.4 L KOH needed

When we add 0.33L of KOH the HCl solution will be neutralized. When we add 1.4 L of KOH the HCl and H2SO4 solution will be neutralized.

4 0

3 years ago