Answer:
V₂ = 0.656 L
Explanation:
Given data:
Initial volume = 3.5 L
Initial pressure = 2.5 KPa
Final volume = ?
Final pressure = 100 mmHg (100/7.501=13.33 KPa)
Solution:
The given problem will be solved through the Boyle's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
2.5 KPa × 3.5 L = 13.33 KPa × V₂
V₂ = 8.75 KPa. L/13.33 KPa
V₂ = 0.656 L
In a chemical equation, the arrow
A. can be read as "yields" or "makes."
B. always points toward the products.
C. separates the products and reactants.
D. all of these
all of these options are right.
Answer: 22.3 *10^23 S atoms
Explanation:
Answer : The number of moles of oxygen needed are, 1.5 moles.
Explanation :
The balanced chemical reaction will be:
Now we have to calculate the moles of oxygen.
From the balanced chemical reaction we conclude that,
As, 6 moles of water vapor produces from 5 moles of oxygen
So, 1.80 moles of water vapor produces from 
moles of oxygen
Therefore, the number of moles of oxygen needed are, 1.5 moles.
<h3>
Answer:</h3>
0.387 J/g°C
<h3>
Explanation:</h3>
- To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
- Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
- That is, Q = mcΔT
in our question we are given;
Mass of copper, m as 95.4 g
Initial temperature = 25 °C
Final temperature = 48 °C
Thus, change in temperature, ΔT = 23°C
Quantity of heat absorbed, Q as 849 J
We are required to calculate the specific heat capacity of copper
Rearranging the formula we get
c = Q ÷ mΔT
Therefore,
Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)
= 0.3869 J/g°C
= 0.387 J/g°C
Therefore, the specific heat capacity of copper is 0.387 J/g°C
