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1 answer:
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Answer:
Theoretical yield is 20%.
Explanation:
Percent yield = [(actual yield)/(theoretical yield)] %
Theoretical yield is calculated amount of product by using stoichiometric ratio between reactant and product.
Actual yield is the amount of product which is experimentally obtained.
Here theoretical yield is 20.0 g and actual yield is 4.0 g.
So, percent yield = % = 20%
Answer:
0.364
Explanation:
Let's do an equilibrium chart for the reaction of combustion of ammonia:
2NH₃(g) + (3/2)O₂(g) ⇄ N₂(g) + 3H₂O(g)
4.8atm 1.9atm 0 0 Initial
-2x -(3/2)x +x +3x Reacts (stoichiometry is 2:3/2:1:3)
4.8-2x 1.9-(3/2)x x 3x Equilibrium
At equilibrium the velocity of formation of the products is equal to the velocity of the formation of the reactants, thus the partial pressures remain constant.
If pN₂ = 0.63 atm, x = 0.63 atm, thus, at equilibrium
pNH₃ = 4.8 - 2*0.63 = 3.54 atm
pO₂ = 1.9 -(3/2)*0.63 = 0.955 atm
pH₂O = 3*0.63 = 1.89 atm
The pressure equilibrium constant (Kp) is calculated with the partial pressure of the gases substances:
Kp = [(pN₂)*(pH₂O)³]/[(pNH₃)²*]
Kp = [0.63*(1.89)³]/[(3.54)²*]
Kp = 4.2533/11.6953
Kp = 0.364