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3 years ago

Which particle of the atom has a negative charge?

Physics

2 answers:

GuDViN [60]3 years ago

5 0

Electron,......l,l,l,l,l,l,l,l,l,

olga55 [171]3 years ago

4 0

The answer is A, electron. A proton has a positive charge and a neutron has a neutral charge. Lastly, the nucleus is the combination of both the neutrons and protons in the atom which would be positive. Hope this helps. :)

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Which of these statements best describes the difference between electromagnetic and gravitational forces in the solar system?

kodGreya [7K]

It's B-<span>Electromagnetic forces are stronger than gravitational forces</span>

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3 years ago

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Why a male who has undergone a vasectomy would be unable to impregnate a female

irina [24]

A vasectomy disables a man in making sperm so therefore would not be able to impregnate I woman

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Two spherical conductors are separated by a distance much larger than either of their radii. Sphere A has a radius of 11.5 cm an

bonufazy [111]

Explanation:

As the given spheres are connected by a thin wire so, the potential on the spheres are the same.

$\frac{q_{1}}{r_{1}} = \frac{q_{2}}{r_{2}}$ ......... (1)

Hence, total charge will be as follows.

$q_{1} + q_{2}$ = Q = -95.5 nC .......... (2)

Using the above two equations, the final equation will be as follows.

$q_{2} = \frac{Qr_{2}}{r_{1} + r_{2}}$

and, $q_{1} = \frac{Qr_{1}}{r_{1} + r_{2}}$

Hence, we will calculate the charge on sphere B after the equilibrium is reached as follows.

$q_{2} = \frac{Qr_{2}}{r_{1} + r_{2}}$

= $\frac{-95.5 \times 74.4 cm}{(11.5 + 74.4) cm}$

= 82.714 nC

Thus, we can conclude that the charge on sphere B after equilibrium has been reached is 82.714 nC.

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3 years ago

Whose series of experiments identified the nucleus of the atom?

Wewaii [24]

Answer:

Rutherford

Explanation:

In 1911, E. Rutherford and his collaborators bombarded a thin gold foil with alpha (positive) particles, coming from a radioactive material, at high speed. The experiment allowed observing the following behavior in the released particles: Most of them passed through the sheet without changing direction, as expected. Some deviated considerably e. A few particles bounced towards the emission source.

In the Rutherford Model the positive charge is concentrated in a central nucleus, so that the positive particles that pass very close to it, deviate enough from their initial trajectory and only those few that collide directly with the nucleus return in the direction of which they come from .

The Rutherford Model states that: The atom has a central zone or nucleus where the total positive charge (that of the protons) and most of the mass of the atom, provided by the protons and neutrons. It also has an outer zone or cortex where electrons are found, which revolve around the nucleus. (Actually, the nucleus particles (protons and neutrons) were discovered after Rutherford established his model. Rutherford's experiment only reported a small, positive nucleus, did not clarify anything else) .

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4 years ago

A long, hollow wire with inner radius a and outer radius b carries a uniform current density J. What is the magnetic field as a

sveta [45]

Answer:

The magnetic field in the region a < r < b is $B=\frac{u_{0}I(r^{2}-a^{2}) }{2\pi r(b^{2}-a^{2}) }$

Explanation:

If we have the a < r < b. The formula of current is:

$J=\frac{I_{total} }{A}$

Where:

A = area enclosed by the loop.

Itotal = total current in loop.

$J=\frac{I}{\pi b^{2}-\pi a^{2} }$

$I_{enclosed} =JA_{enclosed}$

$I_{enclosed} =\frac{I(\pi r^{2}- \pi a^{2})}{\pi b^{2}-\pi a^{2} }$

If we have the Ampere`s law:

$\int\limits^a_b {B} \, ds =u_{0} I_{enclosed} \\2B\pi r=u_{0} (\frac{I(\pi r^{2}-\pi ^{2} }{\pi ^{2}-\pi a^{2} } )\\B=\frac{u_{0}I(r^{2}-a^{2}) }{2\pi r(b^{2}-a^{2}) }$

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3 years ago