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Andru [333]
3 years ago
14

A person uses a constant force to push a 14.0 kg crate 1.80 m up a frictionless 10⁰ incline and to also increase its speed from

0.5 m/s to 1.5 m/s in the process. Find: (a) the work done by gravity; (b) the change in kinetic energy of the crate; (c) the net work done on the crate; (d) the work done by the person
Physics
1 answer:
zubka84 [21]3 years ago
6 0

a) Making h as the shorter cathetus, we have,

h=1.8*sin10=0.312

We proceed to calculate the work done by gravity

W_g=-mgh

W_g=-140*0.312=-43.76J

b) It's necessary to calculate the Kinetic Energy, we use the equation of KE,

\Delta KE = \frac{1}{2}m(v_2^2-v_1^2)

\Delta KE = \frac{1}{2}14(1.5^2-0.5^2)=14J

c) By work energy theorem

W_{net}=\Delta KE \rightarrow W_net = 14J

d) we calculate net work through the law of conservation

W_{net}=W_f+W_g=14

\rightarrow W_f = 14-W_g=14-(-43.76)

W_f=57.76J

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What is the entropy of a closed system in which 28 distinguishable grains of sand are distributed among 1000 distinguishable equ
baherus [9]

Answer:

193.4 J/K

Explanation:

For a closed system, the entropy is given as the natural logarithm of microstates.

The number of particles ( grains of sand ) N = 28

The number of boxes ( compartments ) M = 1000

Entropy is the logarithm of number of microstates

S=ln \psi

But the number of microstates is given by

\psi=M^{N} hence S=ln M^{N}=\ln (1000^{28})= \boxed{193.4 J/K}

4 0
3 years ago
The dielectric in a capacitor serves two purposes. It increases the capacitance, compared to an otherwise identical capacitor wi
VikaD [51]

Answer: 580 x 10^-3 J

Explanation:

0.6mm is 0.6/1000 = 600*10^-6 m

The plate area is .17*.17 = 28.9*10^-3 m^2

Air:

The voltage that can be sustained by 0.60 mm of air dielectric is:

V = 3.0*10^6* 600*10^-6 = 1800 V

The capacitance is:

C = ε*A/d = 8.854*10^-12 * 28.9*10^-3/600*10^-6 = 426*10^-12 F = 426 pF

The energy stored in a capacitor is:

E = (1/2)*C*V^2 = (1/2)*426*10^-12*(1800)^2 = 691*10^-6 J

Teflon:

The voltage is:

V = 60*10^6* 600*10^-6 = 36*10^3 = 36 kV

According to the listed reference, the relative dielectric constant for teflon is 2.1, this figure multiplies the "ε" of free space.

The capacitance is:

C = ε*A/d = 2.1*8.854*10^-12 * 28.9*10^-3/600*10^-6 = 896*10^-12 F = 896 pF

It would have been easier to note that the capacitance is 2.1 times the air-dielectric case.

The maximum energy stored is:

E = (1/2)*C*V^2 = (1/2)* 896*10^-12* (36*10^3)^2 = 580*10^-3 J

8 0
3 years ago
My uncle wants to play twister with me and my little sister but he gets a lil too wild. What do I do ?
Lelu [443]

Get even wilder so he knows your'e not the one to joke with!

Hope This Helps Him Calm Down:)

8 0
2 years ago
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PLEASE HELP : What happens in obese mice? (Physiology)
irina1246 [14]

Answer and

Explanation:

The gut microbiota has recently emerged as an important, and previously unappreciated, player in host physiology (1). In particular, the gut microbiota contributes to a variety of physiological and pathophysiological processes in the host including immune disorders (2–4), atherosclerosis (5), irritable bowel syndrome (6, 7), blood pressure regulation (8), and chronic kidney disease (9, 10). Bacteria residing in the human gut are an important component of human physiology: the total wet weight of gut microbes in the human has been estimated to be 175 g–1.5 kg (11, 12), and the cells of the microbiota outnumber human cells by 10:1 (1). These bacteria interact with the immune system of the host (13), and secrete a variety of metabolites, which enter host circulation and can affect a variety of physiological parameters (8, 14), reviewed in Ref. (15). In fact, metabolites produced by the gut microbiota have been found to play key roles in renal disease (16), blood pressure regulation (8), and immune disorders (2–4). Therefore, just as we consider the genetic background of an animal or an individual to be an important contributing factor to their physiology, so too must we consider the genetic background of the microbiota associated with that animal.

Gut microbiota vary greatly amongst laboratory animals, and these differences result in notable differences in experimental results. Mice of the same strain from different vendors have different microbiota profiles (17), and similarly, the same mice housed at different institutions have different microbiota profiles (18, 19). Conversely, inoculating two different inbred mouse strains with the same gut bacteria leads to differences in host gene expression between the two mouse strains (20). Clearly, there is a complex interplay between the genetics of the microbiota and that of the host organism, which has only recently begun to be appreciated.

Go to:

Gut Microbiota as an Experimental Parameter

Examples in the literature have highlighted the important and unexpected ways in which gut microbiota can affect a variety of experimental parameters. In a series of studies, Vijay-Kumar et al. (13, 21) reported that although TLR5 null animals initially had a colitis phenotype, when these mice were “rederived” and their gut microbiota altered, the colitis phenotype was greatly attenuated, and instead the null animals exhibited metabolic syndrome. In addition, Lathrop et al. put forward a model by which T-cells are educated not only by self/non-self mechanisms, but also by microbiota-derived “non-self” antigens (22). Accordingly, they found that the presence or absence of microbiota determined whether T cells would induce colitis in mice. Finally, Yang et al. reported that when the same knockout mice were housed at two different institutions, they had markedly different microbiota profiles – and the mice at one institution (MIT) were quite susceptible to colitis, whereas mice at the other institution (MHH) failed to develop any significant pathology under the same conditions (19). Unequivocally, altering gut microbiota – even by housing animals at different institutions – can have dramatic effects on the phenotype observed.

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Gut Microbiota and Obesity and Diabetes

It is important to note that not only can microbiota affect host physiology, but the gut microbiota are not necessarily stable over time. Rather, gut microbiota can change or shift as a result of experimental manipulation (in animals) or changes in lifestyle or nutrition (in humans). It is now appreciated that there are “shifts” in microbiota that occur in obesity in mice, rats, and humans (23–26). In one study, Turnbaugh et al. (25) examined human female twin pairs concordant for leanness or obesity, and found that obesity was associated with phylum-level changes in microbiota.

7 0
3 years ago
Which nutrient is the most difficult to break down and, thus, is generally used last for energy in the body?
photoshop1234 [79]

Answer:

proteins

Explanation:

protiens is the most difficult nutrient to brek down

8 0
3 years ago
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