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makvit [3.9K]
3 years ago
10

Why does gravitational energy increase away from earth

Physics
1 answer:
aliina [53]3 years ago
4 0
Because of the rule of mask.
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The SI unit of power is the watt. Which of the following units are equivalent to the watt?
Llana [10]

Answer:

The right option is (A) V.A

Explanation:

Power: This is the rate at which work is done. Or it is the produce of force and velocity. The S.I unit of power is Watt (W). Other units include Horse power(hp), foot-pound per minutes, etc.

Generally, power can be represented as,

Power = Energy/time

P = W/t......................... Equation 1

Where p = power, w = Work or energy, t = time in seconds.

Electrical energy: This is the product of potential difference and the quantity of charge.

∴ W = VQ............................... Equation 2

Where V = potential difference, Q = quantity of charge and W = Energy or Work done.

Also Q = It........................ Equation 3.

where I = current in ampere, t = time in seconds

Substituting equation 3 into equation 3

W = VIt............................ Equation 4.

Also substituting Equation 4 into Equation 1

P = VIt/t = VI = voltage(V)×Current(A)

Therefore the equivalent unit of power is

P = V.A.

The right option is (A) V.A

3 0
3 years ago
Calculate the effective radiation dosage in sieverts for a 57 57 ‑kg person who is exposed to 4.2 × 10 9 4.2×109 particles of al
Rus_ich [418]

Answer:

  Dose = 5.4 10⁻⁴  Sv

Explanation:

The radiation dose absorbed by the body is 81% of the incident radiation, which is the number of particles per energy of each particle

    E = 0.81 n₀ E₀

    E = 0.81 4.2 10⁹ 0.81 6.1 10⁻¹³

    E = 2.075 10⁻³ J

Effective radiation dose

     Dose1 = n x RBE

     Dose1 = 2,075 10⁻³ 15

     Dose1 = 3.1 10⁻² REM

The effective radiation dose in sievert

          Dose = dose1 / m

          Dose = 3.1 10⁻² / 57

          Dose = 5.4 10⁻⁴      [j / kg]

          Dose = 5.4 10⁻⁴  Sv

6 0
4 years ago
Find the speed vfinal of the joined cars after the collision. mastering physics
Tanya [424]
<span>Px = 0 Py = 2mV second, Px = mVcosφ Py = –mVsinφ add the components Rx = mVcosφ Ry = 2mV – mVsinφ Magnitude of R = âš(Rx² + Ry²) = âš((mVcosφ)² + (2mV – mVsinφ)²) and speed is R/3m = (1/3m)âš((mVcosφ)² + (2mV – mVsinφ)²) simplifying Vf = (1/3m)âš((mVcosφ)² + (2mV – mVsinφ)²) Vf = (1/3)âš((Vcosφ)² + (2V – Vsinφ)²) Vf = (V/3)âš((cosφ)² + (2 – sinφ)²) Vf = (V/3)âš((cos²φ) + (4 – 2sinφ + sin²φ)) Vf = (V/3)âš(cos²φ) + (4 – 2sinφ + sin²φ)) using the identity sin²(Ď)+cos²(Ď) = 1 Vf = (V/3)âš1 + 4 – 2sinφ) Vf = (V/3)âš(5 – 2sinφ)</span>
6 0
4 years ago
g As they reach higher temperatures, most semiconductors... Selected Answer: have an increased resistance. Answers: have a const
pochemuha

Answer:

have an increased resistance

3 0
3 years ago
One of the best candidates for a black hole is found in the binary system called A0620-0090. The two objects in the binary syste
Darya [45]

Answer:

One of the best candidates for a black hole is found in the binary system called A0620-0090. The two objects in the binary system are an orange star, V616 Monocerotis, and a compact object believed to be a black hole. The orbital period of A0620-0090 is 7.75hours, the mass of V616 Monocerotis is estimated to be .67 times the mass of the sun, and the mass of the black hole is estimated to be 3.8 times the mass of the sun. Assuming that the orbits are circular, find the radius of the orbit of the orange star.

Explanation:

6 0
3 years ago
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