You could answer this right away IF you knew the length of each wave, right ?
Well, Wavelength = (speed) / (frequency).
Speed = 3 x 10⁸ m/s (the speed of light)
and
Frequency = 90.9 x 10⁶ Hertz.
So the length of each wave is 3 x 10⁸ / 90.9 x 10⁶ meters.
To answer the question, see how many pieces you have to cut
that 1.5 km into, in order for each piece to be 1 wavelength.
It'll be
(1,500 meters) divided by (3 x 10⁸ meters/sec) / (90.9 x 10⁶ Hz)
To divide by a fraction, flip the fraction and then multiply:
(1500 meters) times (90.9 x 10⁶ Hz)/(3 x 10⁸ meters/sec)
= 454.5
Answer:
<em><u>It can be a solid, liquid, gas</u></em><em><u>,</u></em><em><u>plasma</u></em><em><u>,</u></em><em><u>etc</u></em><em><u>. When waves travel through a medium, the particles of the medium are not carried along with </u></em><em><u>the</u></em><em><u> </u></em><em><u>wave</u></em><em><u>.</u></em><em><u>For example, water waves have to travel in water. Sound waves need a solid, a liquid or a gas to travel in.</u></em>
Using the term c in this case is a little confusing. It is more generic to use a general velocity, v. That way, in this case, we know to use the speed of sound.
wavelength*frequency=v
wavelength_20Hz = (345 m/s)/(1/20s)
<span>wavelength_20kHz = (345 m/s)/(1/20000s)
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Answer:
The strength of magnetic field is
T
Explanation:
Given:
Length of rod
m
Velocity

Induced emf
V
According to the faraday's law
Induced emf = 
We have to find strength of the magnetic field,

T
Therefore, the strength of magnetic field is
T
I think the correct answer from the choices listed above is the second option. In Niels Bohr’s model of the atom, electrons move like planets orbiting the sun. His model of atom is seen as<span> very small, positively charged nucleus which contains proton and neutron surrounded by negatively charged electrons.</span><span> These electrons travel in circular orbits around the nucleolus. </span>