A 2.80 kg mass is dropped from a height of 4.50 m . Find its potential energy (PE) at the moment it is dropped .

light of wavelength 485 nm passes through a single slit of width 8.32 *10^-6m. what is the single between the first (m=1) and se

Assoli18 [71]

Answer:

3.35

Explanation:

Got it on Acellus

3 0

2 years ago

A string is attached to a ball that has a mass of 0.11 kg. A student pulls up on the string so that the ball accelerates upward

enot [183]

Answer:

T=+1.133N

Explanation:

Tension and weight are forces that have opposite directions

Weight is negative (downward)

W=m*g= 0.11kg*(-9.8m/s^2)

W= -1.078N

Tension is possitive (upward)

The total force will be the sum of both (the difference taking in consideration the direction)

Ft= T+W

Also the total force is the product of the mass due to acceleration:

Ft=m*a

Ft= +0.11kg*0.5m/s^2

Ft=+0.055N (upward)

Tension will be the difference between Ft and W:

T= Ft-W

T=+0.055N-(-1.078N)

T=+1.133N

7 0

3 years ago

You are pushing a 60 kg block of ice across the ground. You exert a constant force of 9 N on the block of ice. You let go after

kotykmax [81]

Answer: d = 33 cm or 0.33 m

Explanation: In physics, Work is the amount of energy transferred to an object to make it move. It can be expressed by:

W = F.d.cosθ

F is the force applied to the object, d is the displacement and θ is the angle formed between the force and the displacement.

For the ice block, the angle is 0, i.e., force and distance are at the same direction, so:

W = F.d.cos(0)

W = F.d

To determine d:

d = $\frac{W}{F}$

d = $\frac{3}{9}$

d = 0.33 m

The distance d the block ice moved is 33 cm.

7 0

3 years ago

Vector B has x, y, and z components of 2.4,

Fed [463]

The magnitude of the vector B is 10.9

A vector is a quantity which has magnitude as well as direction and it follows vector laws of addition.

To calculate the magnitude of the vector, we have to put the square of the components of the vector along the axes under the root.

Vector B has components,

x = 2.4

y = 9.8

z = 4.1

Applying the formula,

|B| = √x²+y²+z²

|B| = √(2.4)² + (9.8)² + (4.1)²

|B| = √5.76+96.04+16.81

|B| = √118.61

|B| = 10.9

Talking about the direction the the Vector B, it will be the line joining the origin with the points (2.4,9.8,4.1)

To know more about Vectors, visit,

brainly.com/question/25705666

#SPJ9

3 0

10 months ago

A physics student stands on a cliff overlooking a lake and decides to throw a softball to her friends in the water below. She th

aliina [53]

Answer:

58.5 m

Explanation:

First of all, we need to find the total time the ball takes to reach the water. This can be done by looking at the vertical motion only.

The initial vertical velocity of the ball is

$u_y = u sin \theta$

where

u = 21.5 m/s is the initial speed

$\theta=33.5^{\circ}$ is the angle

Substituting,

$u_y = (21.5) sin 33.5^{\circ} =11.9 m/s$

The vertical position of the ball at time t is given by

$y = h + u_y t + \frac{1}{2}gt^2$

where

h = 13.5 m is the initial heigth

$g = -9.8 m/s^2$ is the acceleration of gravity (negative sign because it points downward)

The ball reaches the water when y = 0, so

$0 = h + u_yt +\frac{1}{2}gt^2\\0 = 13.5 +11.9 t - 4.9t^2$

Which gives two solutions: t = 3.27 s and t = -0.84 s. We discard the negative solution since it is meaningless.

The horizontal velocity of the ball is

$u_y = u cos \theta = (21.5) cos 33.5^{\circ} =17.9 m/s$

And since the motion along the horizontal direction is a uniform motion, we can find the horizontal distance travelled by the ball as follows:

$d= u_x t = (17.9)(3.27)=58.5 m$

3 0

3 years ago