Answer:
Hence the correct option is option b) Yes, the upper level of one standard deviation is 72.
A score of 74 is not within one standard deviation of the mean.
Step-by-step explanation:
Here the given details are,
Mean = 68
SD = 4
Distribution is normal.
Z-score for x = 74 is given as below:
So, the score of 74 is 1.5 standard deviations from the mean.
Therefore the score is not lies between 64 and 72.
Yes, the upper level of one standard deviation is 72.
Answer:
32y² + 192y
Step-by-step explanation:
First, we need to distribute 8y. This gets us 32y²+192y. I do not believe you can simplify that. I hope this helps!
1. Mean of the data: 8
2. Median: 8
3. IQR = 4
4. Members that use the facility 10 days a month is: 2.
See reasons below.
<h3>What is the Mean, Median, and Interquartile Range of a Data?</h3>
Mean = sum of all values ÷ number of data values (easily solved using a dot plot
Median = middle value (easily found using a box plot).
Interquartile range (IQR) = Q3 - Q1 (easily found using a box plot).
1. Mean of the data: use the dot plot.
Reasoning: (3 + 3 + 5 + 6 + 6 + 7 + 8 + 8 + 8 + 9 + 10 + 10 + 11 + 12 + 14)/15 = 8
2. Median of the data set: Using the box plot, it is the value indicated by the vertical line that divides the box.
Median = 8
3. IQR = Q3 - Q1 = 10 - 6
IQR = 4
4. Members that use the facility 10 days a month, using the dot plot is: 2. 10 has 2 dots.
Learn more about the mean, median, and interquartile range on:
brainly.com/question/9821103
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Answer:
The answer is 
Step-by-step explanation:
The formula is:
In this case :
To get the simples form notice both 104 and 288 are divisible by 8 and 104/8 = 13 and 288/8 = 36.
Thus 
Let's interpret this first!
4 times as much as 1 third of 8
Well you have 1/3 of 8
Then you have 4 times as much as that.
4( 1/3 x 8 )
