The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)
<h3>
on what interval is the function positive?</h3>
The function is positive when g(x) > 0.
Then we need to solve:
∛(x - 3) > 0
We can directly remove the cubic root, because it does not affect the sign of the argument, then:
x - 3 > 0
x > 3
The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)
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Answer:
247,085 doctors in total
Step-by-step explanation:
55,100 = 22.3℅ ÷22.3
2,471 = 1℅
2471.85x100 = 247,085 doctors
To check I'll do 247,085÷100 = 2,470.85 = 1℅
2,470.85 × 22.3 = 55,099.955 which would round up to 51,000.
Just divided 1.3/100 and it gives you 0.013
Answer:
716 or 10742/15
Step-by-step explanation:
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Answer:
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Step-by-step explanation: