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grin007 [14]
2 years ago
12

You are leaving for a party at your cousin’s house in a city that is 150 km away. You will travel at an average rate of 50 km/hr

. How long will it take you to arrive? hours
Physics
2 answers:
seropon [69]2 years ago
4 0

The first part is 3 hours, and the second part of the question is 60 km/ hr. That's the answer edge provided

mrs_skeptik [129]2 years ago
3 0

The distance you should cover is: S=150 km

Your average speed is: v=50 km/h

Therefore, to calculate the time you will take to cover this distance, we can use the basic relationship between space, distance and time, and we find:

t=\frac{S}{v}=\frac{150 km}{50 km/h}=3 h

so, you will take 3 hours.

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It's nighttime, and you've dropped your goggles into a 3.2-mm-deep swimming pool. If you hold a laser pointer 1.1 mm above the e
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Answer: 5.30m

Explanation:

depth of pool = 3.2 m

i = 67.75°

Using snell's law, we have,

n₁ × sin(i) = n₂ × 2 × sin(r)

n₁ = 1, n₂ =1.33, r= 44.09°

Hence,

Distance of Google from edge if pool is:

2.2 + d×tan(r) = 2.2 + (3.2 × tan(44.09°) =5.30m

5 0
3 years ago
All organisms in Kingdom Animalia are multicellular, meaning their bodies are composed of more than one cell. Which other charac
k0ka [10]
Well,

For the first one, the answer would be C, because all organisms in Kingdom Animalia must eat in order to survive.

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4 0
3 years ago
Read 2 more answers
A 85 kg lineman tackles a 90 kg receiver. The receiver is running 5.8 m/s, and the lineman is moving 4.1 m/s, at a right angle t
weeeeeb [17]

Answer:

3.59 m/s

Explanation:

We are given that

Mass of lineman,m=85 kg

Mass of receiver,m'=90 kg

Speed of receiver,v'=5.8 m/s

Speed of lineman,v=4.1 m/s

\theta=90^{\circ}

We have to find the their velocity immediately after the tackle.

Initial momentum,P_i=\sqrt{p^2_1+p^2_2}=\sqrt{(85\times 4.1)^2+(90\times 5.8)^2}=627.6 kgm/s

According to law of conservation of momentum

Initial momentum=Final momentum=(m+m')V

627.6=(85+90)V=175V

V=\frac{627.6}{175}=3.59 m/s

3 0
3 years ago
When the velocity of an object Changes it is acted upon by a
anygoal [31]

When the velocity of an object changes, it is acted upon by a force

5 0
3 years ago
A tank of gasoline (n = 1.40) is open to the air (n = 1.00). A thin film of liquid floats on the gasoline and has a refractive i
klio [65]

Answer:

1.08

Explanation:

This is the case of interference in thin films in which interference bands are formed due to constructive interference of two reflected light waves , one from upper layer and the other from lower layer . If t be the thickness and μ be the refractive index then

path difference created will be 2μ t.

For light coming from rarer to denser medium , a phase change of π occurs additionally after reflection from denser medium, here, two times, once from upper layer and then from the lower layer ,  so for constructive interference

path diff = nλ , for minimum t , n =1

path diff = λ

2μ t. =  λ

μ = λ / 2t

= 626 / 2 x 290

= 1.08

5 0
3 years ago
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