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kykrilka [37]
3 years ago
9

Calculate the aceleration of a vehicle if the initial velocity (Vi) is 20 m/s and acelerates to 40 m/s (V) in 3,8 s. (t).

Physics
2 answers:
dedylja [7]3 years ago
8 0

Answer:

Huh? What do u say!

Explanation:

tekilochka [14]3 years ago
4 0

Hello!!

For calculate the aceleration of the vehicle let's applicate formula:

\boxed{V=V_i + a*t}

\textbf{Being:}

\sqrt{} V = Final velocity = 40 m/s

\sqrt{} Vi = Initial velocity = 20 m/s

\sqrt{} a = Aceleration = ?

\sqrt{} t = Time = 3,8 su

⇒ \text{Then let's \textbf{replace it according} we information:}

40 \  m / s = 20 \ m / s + a * 3,8 s

⇒ \text{We clear the "a"}

a = \dfrac{40 \ m /s - 20 \ m /     s }{3,8 \ s}

⇒ \text{Let's resolve it: }

a = 5,263         \                                              m /                                                       s

\textbf{Result:}\\\text{The aceleration is of \textbf{5,263 m/s}}^{2}

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Answer:

9.78 m/s²

Explanation:

To solve this, we use the gravitational formula

g = GM/r², where

g = acceleration due to gravity

G = gravitational constant

M = mass of the planet

r = radius of the planet

From the question, we got that the mass of the planet is

M = 9ME, where ME = 5.95*10^24

M = 9 * 5.95*10^24

M = 5.355*10^25 kg

Also, the Radius of the planet, R = 3RE, where RE = 6.37*10^6

R = 3 * 6.37*10^6

R = 1.911*10^7 m

On applying the values of both R and M to the equation, we get

g = GM/r²

g = (6.67*10^-11 * 5.355*10^25) / (1.911*10^7)²

g = 3.57*10^15/3.65*10^14

g = 9.78 m/s²

Therefore, the acceleration due to gravity on the planet is 9.78 m/s²

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5 0
3 years ago
6. An earthquake releases two types of traveling seismic waves, called transverse and longitudinal waves. The average speed of t
zubka84 [21]

Answer:

The distance away the center of the earthquake is 1083.24 km.

Explanation:

Given that,

Speed of transverse wave = 9.1\ km/s

Speed of longitudinal wave = 5.7 km/s

Time = 71 sec

We need to calculate the distance of transverse wave

Using formula of distance

d=v\times t

d=9.1\times t....(I)

The distance of longitudinal wave

d=5.7\times (t+71)....(II)

From the first equation

t=\dfrac{d}{9.1}

Put the value of t in equation (II)

d =5.7\times(\dfrac{d}{9.1}+71)

\dfrac{9.1d-5.7d}{9.1}=71\times5.7

d0.3736=404.7

d =1083.24\ km

Hence, The distance away the center of the earthquake is 1083.24 km.

6 0
3 years ago
The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of 100 m. Its name comes from its 60 arms, each of which can
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Answer:

Explanation:

a ) speed of passenger = circumference / time

= 2π R / Time

= 2 x 3.14 x 50 / 60

= 5.23 m /s

b )

centrifugal force = m v² /R

= (882 /9.8 ) x 5.23² / 50

= 77.47 N

Apparent weight at the highest point

real weight  - centrifugal force

= 882 - 77.47

= 804.53 N

Apparent weight at the lowest point

real weight  + centrifugal force

= 882 +77.47

= 959.47 N

c )  if the passenger’s apparent weight at the highest point were zero

centrifugal force = weight

mv² /R = mg

v² = gR

= 9.8 X 50

v = 22.13 m /s

d )

apparent weight

mg - mv² / R

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malfutka [58]

Answer: columbs

Explanation:

Electrical charge are measured in columbs, usually demoted as C. Hence, the charges on proton and electron will be measured in Coloumbs. It typically measures the amount of electricity conveyed per second by a current of 1 ampere. The other units Given such as ; Volt is used for measuring voltage, which is the pressure in an electrical source. AMPERE is used for measuring the current flowing through an electrical circuit.

Dalton is a unit of mass and is about 1.660 * 10^-27 kg

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Answer:

3. 5.0N/kg

Explanation:

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