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Schach [20]
3 years ago
11

43.2 + 50.0 + 16.0= answer in correct amount of significant figures

Chemistry
1 answer:
Molodets [167]3 years ago
4 0

Answer : The correct answer is 109.

Explanation :

Significant figure : It is defined as the each digits of a number have meaning or contribute to the value of the number.

The addition of given digits is,

43.2 + 50.0 + 16.0 = 109.2

As per the question, the given digits has 3 significant figures. But the answer after addition is 109.2 has 4 significant figures.

The addition rule of significant rule is the least precise number of significant figure in any number of the problem determines the number of significant figures in the answer.

Therefore, from the addition rule, the correct answer is 109.

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Answer:

1,9,6,6

Explanation:

3 0
3 years ago
Formic acid (HCO2H) has a dissociation constant of 1.8 x 10^-4 M. The acid dissociates 1:1. What is the [H+] if 0.35 mole of for
Tju [1.3M]
Initial [ HCO2H] = moles * volume 
                           =0.35 moles * 1 L = 0.35 M

by using ICE table:

              HCO2H ↔ H+  + HCO2-
initial      0.35 M        0          0
change  - X             +X          +X
Equ       (0.35 - X)       X          X

∴ Ka = [H+][HCO2-] / [HCO2H]

by substitution:

1.8 x 10^-4 =  X^2 / (0.35-X) by solving for X

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7 0
3 years ago
Which does not affect chemical equilibrium
Amanda [17]
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5 0
3 years ago
Read 2 more answers
1. A dining hall had a total of 25 tables-some long rectangular tables and some round
TEA [102]

x = 20 long tables

y = 5 round table

Explanation:

We have the following system of equations:

x + y = 25

8x + 6y = 190

From the first equation we have:

x = 25 - y

And we replace x in the second equation:

8(25 - y) + 6y = 190

200 - 8y + 6y = 190

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200 - 190 = 2y

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y = 5

Now we insert the value of y in the next equation:

x = 25 - y

x = 25 - 5

x = 20

Learn more about:

system of equations

brainly.com/question/1748197

brainly.com/question/1658819

#learnwithBrainly

7 0
3 years ago
How many calories is 130. joules?
skad [1K]
1 Cal ---------- 4.184 J
? Cal ---------- 130.0 J

130.0 x 1 / 4.184 => 31.07 Cal

hope this helps!


6 0
3 years ago
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