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myrzilka [38]
2 years ago
6

Describe the process of convection and how it contributes to seafloor spreading

Chemistry
2 answers:
kobusy [5.1K]2 years ago
8 0

Answer:

Seafloor spreading and other tectonic activity processes are the result of mantle convection. ... Seafloor spreading occurs at divergent plate boundaries. As tectonic plates slowly move away from each other, heat from the mantle's convection currents makes the crust more plastic and less dense.

qwelly [4]2 years ago
7 0

Answer:

Seafloor spreading occurs at divergent plate boundaries. As tectonic plates slowly move away from each other, heat from the mantle's convection currents makes the crust more plastic and less dense. The less-dense material rises, often forming a mountain or elevated area of the seafloor. Eventually, the crust cracks.

Explanation:

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If 100 ml of some pb(no3)2 solution is mixed with 100 ml of 6.50 x 10−2 m nacl solution, what is the maximum concentration of th
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3 years ago
The moon phase takes about a year to complete.....True or false?
larisa [96]

Answer:

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Explanation:

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3 years ago
what volume of N2 is required to convert 5.0L of hydrogen gas to ammonia? assume that all gases are at the same temperature and
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Answer:

Approximately 1.7\; {\rm L}.

Explanation:

Nitrogen {\rm N_{2}}\, (g) reacts with hydrogen {\rm H_{2}}\, (g) at a 1:3 ratio to produce ammonia {\rm NH_3}\, (g):

{\rm N_{2}}\, (g) + 3\; {\rm H_{2}}\, (g) \to 2\; {\rm NH_{3}}\, (g).

The ratio between the coefficient of {\rm N_{2}}\, (g) and the coefficient of {\rm H_{2}}\, (g) is:

\begin{aligned}\frac{n({\rm N_{2}})}{n({\rm H_{2}})} = \frac{1}{3}\end{aligned}.

Under the ideal gas assumptions, the same ratio would apply to the volume of {\rm N_{2}}\, (g) and {\rm H_{2}}\, (g) in this reaction:

\begin{aligned}\frac{V({\rm N_{2}})}{V({\rm H_{2}})} = \frac{n({\rm N_{2}})}{n({\rm H_{2}})} = \frac{1}{3}\end{aligned}.

\begin{aligned}V({\rm N_{2}})= \frac{1}{3}\, V({\rm H_{2}})\end{aligned}.

Given that V({\rm H_{2}}) = 5.0\; {\rm L}:

\begin{aligned}V({\rm N_{2}}) &= \frac{1}{3}\, V({\rm H_{2}}) \\ &= \frac{1}{3}\times 5.0\; {\rm L} \\ &\approx 1.7\; {\rm L}\end{aligned}.

(Rounded to 2 significant figures.)

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