YEAH OFC SHAWTY!
- so for A its -4^11 because if the powers have the same base and they are being multiplied you add the powers
- For B its the same idea, they have the same base, and are being multiplied so you add the powers- 13^9
- For C its similar, you have the same base, but since its Dividing, you subtract the powers. So, 9^5
- for D you pretend like the denominator has a power of 1 and subtract. So its -24^5-24^1 which hopefully puts it into perspective of being -24^4 becuase we subtracted the powers
I cant do 2 right now, but i will in a minute
<u>And for 3 his mistake is that they arent the same bases so he cant add the powers, he should have converted them to the same base first. </u>
I believe you will need to find what -0.125 of an inch is, subtract that from 16, then divide that into 11.
Answer: y + 3 = 4 (x +1 )
Step-by-step explanation:
The eqution of a line in point- slope form is given as :
= m(
)
Where m is the slope and (
, 
) is the given point
substituting the values into the formula , we have:
y - (-3) = 4 ( x - {-1) )
y + 3 = 4 ( x + 1)
This is the equation of the line in point-slope form.
Answer:
24cubic inches
Step-by-step explanation:
Answer:
The height of the triangle is 7cm and the base is 16cm
Step-by-step explanation:
First of all we have to know the formula to calculate area of a triangle
a = area = 56
b = base
h = heigth
a = (b * h)/2
we replace the known values and we make 2 equations
56cm² = (b * h)/2
b = h + 9cm
we replace b by (h + 9cm) in the first equation
56cm² = (h + 9cm * h)/2
56cm² * 2 = h² + 9h
0 = h² + 9h - 112cm²
we use bhaskara formula:
(-b (±) √
(b² - 4ac) ) / 2a
we replace with the known values
h = (-9 (±) √
(9² - 4*1*(-112) ) ) / 2*1
h = (-9 (±) √
(81 + 448) ) ) / 2
h = (-9 (±) √529) /2
h = (-9 (±) 23)/2
h1 = (-9 + 23) / 2
h1 = 14 / 2
h1 = 7
h2 = (-9 - 23) / 2
h2 = -32 / 2
h2 = -16
The height of the triangle is 7cm and the base is 16cm
