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kicyunya [14]
3 years ago
5

Use the LCD to rewrite 34, 58, and 110 with the same denominator pls help

Mathematics
1 answer:
galben [10]3 years ago
4 0

Answer: 30/40, 25/40, 4/40

Step-by-step explanation: Using the Least Common Denominator, I looked at each multiple of each number to determine 40 as the least common denominator, and since we did 4 x 10 to get 40 in the first one, we do 3 x 10 in the first one as well making it 30/40. The second one we did 8 x 5 to get 40, making the numerator (top number) the product of 5 x 5 which is 25 making it 25/40. For the last one, I used 10 x 4 to get 40 meaning I would have to do 1 x 4 to get the numerator (top number) making it 4/40

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**50 Points Possible** I NEED URGENT HELP <br>please provide a graph
Elina [12.6K]

Answer:

See below.

Step-by-step explanation:

1)

For Ben's social media post, we are told that it was initially shared to only 2 people. However, each of those shares it with 3 people. In other words, Ben's post triples every day. This means that the rate of growth is 3. Thus, Ben's post as an exponential function is:

f(x)=2(3)^x

The 2 represents the initial amount at day 0, and the 3 represents the rate at which the post grows each day.

2)

Similarly, Carter's post was originally sent to 10 people. However, each of the 10 shares it with two others. Therefore, it doubles each day. Thus, the rate is 2. So, Carter's exponential function is:

f(x)=10(2)^x

The 10 represents the initial amount while the 2 represents the rate.

3)

I've use Desmos to graph the functions. Refer to the picture attached. Red is Amber, blue is Ben, and green is Carter.

4)

To find out the number of shares each student's post will receive on day 3 and day 10, simply plug the numbers into the functions. Therefore:

For Amber:

Day 3:

f(3)=3(4)^3=192

Day 10:

f(10)=3(4)^{10}=3,145,728

For Ben:

Day 3:

f(3)=2(3)^3=54

Day 10:

f(10)=2(3)^{10}=118,098

And for Carter:

Day 3:

f(3)=10(2)^3=80

Day 10:

f(10)=10(2)^{10}=10,240

5)

Amber's new graph of:

f(x)=3(4)^x+45

will be a shifted version of her original graph. The new graph will be shifted upwards by 45 units. However, since the 45 is not affected by the x in any way, the change will be minuscule. For instance, her number of shares on day 10 of the old graph is 3,145,728. Even with the additional 45, it will just be: 3,145,773. With enough days, the additional number becomes trivial.

6)

On the 10th day, Amber's post was shared almost 3 million times, while Ben's was shared "only" 118,098 times and Carter's with 10,240. Undoubtedly, Amber's post was the fastest.

7)

If you want to most shares as possible, choose Amber with fewer friends initially but more shares. This is because the exponential potential of a number even just a bit higher is insane. For instance, 3^10 (Ben's rate at 10th day) is only 59,049 while Amber's rate will be 4^10 which is 1,048,576. Amber's number is almost 18 times higher than Ben's. Even if Ben's initial number was say 1,000 or even 1,000,000, Amber would catch up rather quickly. Therefore, the rate is the quintessential part of an exponential growth function.

5 0
3 years ago
Kenny reads 4/9 page in 3/5 min. what is Kenny's unit rate? <br><br> Step by step.
il63 [147K]

Answer:

The unit rate is \frac{27}{20}\text{ page/minute}

Step-by-step explanation:

Given : Kenny reads \frac{4}{9} page in \frac{3}{5} min.

To find : What is Kenny's unit rate?

Solution :

Kenny reads \frac{4}{9} page in \frac{3}{5} minute

This can be written as,

\frac{4}{9}\text{ page}=\frac{3}{5}\text{ minute}

Divide both side by \frac{9}{4}

\frac{4}{9}\times \frac{9}{4}\text{ page}=\frac{3}{5}\times \frac{9}{4}\text{ minute}

1\text{ page}=\frac{27}{20}\text{ minute}

The unit rate is \frac{27}{20}\text{ page/minute}

4 0
3 years ago
When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constan
vitfil [10]

Answer:

a = 6m/s^2

Step-by-step explanation:

Given

When mass = 4kg; Acceleration = 15m/s²

Required

Determine the acceleration when mass = 10kg, provided force is constant;

Represent mass with m and acceleration with a

The question says there's an inverse variation between acceleration and mass; This is represented as thus;

a\ \alpha\ \frac{1}{m}

Convert variation to equality

a = \frac{F}{m}; Where F is the constant of variation (Force)

Make F the subject of formula;

F = ma

When mass = 4kg; Acceleration = 15m/s²

F = 4 * 15

F = 60N

When mass = 10kg; Substitute 60 for Force

F = ma

60 = 10 * a

60 = 10a

Divide both sides by 10

\frac{60}{10} = \frac{10a}{10}

a = 6m/s^2

<em>Hence, the acceleration is </em>a = 6m/s^2<em />

4 0
3 years ago
Please help me asap
german
The answer is 86.4 I believe.
5 0
2 years ago
For the line segment whose endpoints are R(1, 2) and S(6, 7), find the y value for the point located 3 ov`er 4 the distance from
Mrac [35]

Answer:

23/4

Step-by-step explanation:

This means that it is 3/4 of the distance in the x <u>and</u> y coordinates, so it is 3/4 of the way from 2 to 7, and since this is a difference of 7-2=5, then it is 2 + (5 * 3/4) or 2 + 15/4 or 23/4.

7 0
3 years ago
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