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3 years ago

5

Use the LCD to rewrite 34, 58, and 110 with the same denominator pls help

1 answer:

galben [10]3 years ago

4 0

Answer: 30/40, 25/40, 4/40

Step-by-step explanation: Using the Least Common Denominator, I looked at each multiple of each number to determine 40 as the least common denominator, and since we did 4 x 10 to get 40 in the first one, we do 3 x 10 in the first one as well making it 30/40. The second one we did 8 x 5 to get 40, making the numerator (top number) the product of 5 x 5 which is 25 making it 25/40. For the last one, I used 10 x 4 to get 40 meaning I would have to do 1 x 4 to get the numerator (top number) making it 4/40

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Joe has 5 dimes and 4 pennies. Jamal has 2 dollars, 4 dimes, and 5 pennies. Jimmy has 6 dollars and 4 dimes. They want to put th

sesenic [268]

Answer:

no they had $9.39

Step-by-step explanation:

i just added them all together

3 0

3 years ago

A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and

mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

$\mu = \frac{3X_{1} + 4X_{2} }{8}$

Now

Bias for the estimator = E(μ bar) - μ

= $E( \frac{3X_{1} + 4X_{2} }{8}) - 4.5$

= $\frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5$

= $\frac{3(4.5) + 4(4.5)}{8} - 4.5$

= $\frac{13.5 + 18}{8} - 4.5$

= $\frac{31.5}{8} - 4.5$

= 3.9375 - 4.5

= - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

= Var(μ bar) + [Bias(μ bar, μ)]²

= $Var( \frac{3X_{1} + 4X_{2} }{8}) + 0.3136$

= $\frac{1}{64} Var( {3X_{1} + 4X_{2} }) + 0.3136$

= $\frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})] }) + 0.3136$

= $\frac{1}{64} [{3(57.76) + 4(57.76)}] } + 0.3136$

= $\frac{1}{64} [7(57.76)}] } + 0.3136$

= $\frac{1}{64} [404.32] } + 0.3136$

= $6.3175 + 0.3136$

= 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0

3 years ago

About 5 out of 10 people entering a community college need to take a refresher mathematics course. If there are 970 entering st

Ksenya-84 [330]

Answer:

"6 out of 10 people" means the ratio of class:no_class is 6:4

990/10 = 99, the smallest the "class" and the "no_class" add up to is 10. And, generally, the total divides with that nicely, as in this case.

99(6) = 594 ----------- probably class

99(4) = 396 ------------------ probably no class

Total = 990

I hope this helps

Step-by-step explanation:

BRAINLIEST?

4 0

3 years ago

If the Lafita family deposits 8500$ ina savings account at 6.75% interest, compounded continuously, how much will be the account

julsineya [31]

A=pe^rt
A=8,500×e^(0.0675×25)
A=45,950.57

8 0

3 years ago

A tug boat traveled -15 miles in 0.3 hours what was its velocity

GenaCL600 [577]

Answer:

22.35 m/s

Step-by-step explanation:

The distance is always a positive unit, so distance traveled (d) = 15 miles

Time (t) = 0.3 hours

Time (t) = 0.3 * 60 = 18 minutes

(1 hour = 60 minutes)

Velocity (v) = ?

The formula of distance is: d = v*t

=> v = d/t = 15/18 = 0.83 miles/minute

we can also calculate velocity is meter/sec, for that

1 minute = 60 sec

=> 18 mins = 18*60 = 1080 sec

1 mile = 1609.34 meters

=> 15 miles = 15 * 1609.34 = 24,140 m

hence,

v = 24,140/1080 = 22.35 m/s

4 0

3 years ago