Use the LCD to rewrite 34, 58, and 110 with the same denominator pls help

Mathematics

1 answer:

galben [10]2 years ago

4 0

Answer: 30/40, 25/40, 4/40

Step-by-step explanation: Using the Least Common Denominator, I looked at each multiple of each number to determine 40 as the least common denominator, and since we did 4 x 10 to get 40 in the first one, we do 3 x 10 in the first one as well making it 30/40. The second one we did 8 x 5 to get 40, making the numerator (top number) the product of 5 x 5 which is 25 making it 25/40. For the last one, I used 10 x 4 to get 40 meaning I would have to do 1 x 4 to get the numerator (top number) making it 4/40

You might be interested in

Twin brothers, Kenny and Isaiah, live in Small Town, USA where it snows an

Morgarella [4.7K]

Answer:

the answer would be maybe 20 minutes

8 0

2 years ago

What is the measure of env

Juliette [100K]

Environmental measurement is the answer

5 0

3 years ago

Need help urgently please

OLga [1]

Answer:

what do you want me to do actuallt the pic is Unclear?

7 0

2 years ago

Which of the following best describes the equation below? A. linear B. both linear and nonlinear C. neither linear nor nonlinear

Julli [10]

Answer:

Where is the equation at

4 0

3 years ago

A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f

Andrews [41]

Answer:

$A = \frac{P}{r}\left( e^{rt} -1 \right)$

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

$\frac{dA}{rA+P} = dt$

Integration on both sides gives

$\int \frac{dA}{rA+P} = \int dt$

where $c$ is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

$\int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c$