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dimulka [17.4K]
3 years ago
13

What are two examples of acceleration???

Physics
2 answers:
Oduvanchick [21]3 years ago
6 0

1). Pushing the brake pedal on a car to make the car slow down and stop.

2). Turning the steering wheel to make the car turn a corner.

atroni [7]3 years ago
4 0

1. Jumping off a building

2. Hitting a tennis ball

3. Swinging a bucket of water in a circle

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What is the accletation of a 1500kg with a net force of 7500 N
matrenka [14]
Acceleration formulae is:
a=Fnet/mass
According to the question
a=7500N/1500kg
a=5m/s sq.
3 0
3 years ago
In experimental design: What are<br> the two groups?
sp2606 [1]

Answer:

The correct answer is : a special type of experimental design where subject divides in two groups according their treatment setting.

Explanation:

A two group is a experimental design two groups are the two different groups of subjects divided by the researcher for comparing the data and result to establish relation in variables.

In normal case, one of the two groups one is a group of subjects who get treatment known as experiment or treatment group while other group is known as control group without treatment.

Thus, the correct answer is : a special type of experimental design where subject divides in two groups according their treatment setting.

7 0
3 years ago
Calculating average speed
djverab [1.8K]

Average speed =

               (distance covered during some period of time)
divided by
               (length of time to cover that distance).

7 0
3 years ago
Why is the horizontal component of a velocity remains constant in horizontal and inclined projection
Artemon [7]

Answer:

This is because there is no acceleration in the horizontal direction

Explanation:

This is because, the only acceleration affecting the object in horizontal and inclined projection is the acceleration due to gravity, which is directed the vertical downward direction. There is a velocity change only in the vertical direction and none in the horizontal direction because, there is no acceleration in the horizontal direction. So, its velocity remains constant.

8 0
3 years ago
A body is thrown up with a velocity of 78.4 m per second.How high will it rise and how much time it will take to return to its p
a_sh-v [17]

Answer:

The maximum height reached by the body is 313.6 m

The time to return to its point of projection is 8 s.

Explanation:

Given;

initial velocity of the body, u = 78.4 m/s

at maximum height (h) the final velocity of the body (v) = 0

The following equation is applied to determine the maximum height reached by the body;

v² = u² - 2gh

0 = u² - 2gh

2gh = u²

h = u²/2g

h = (78.4²) / (2 x 9.8)

h = 313.6 m

The time to return to its point of projection is calculated as follows;

at maximum height, the final velocity becomes the initial velocity = 0

h = v + ¹/₂gt²

h = 0 + ¹/₂gt²

h =  ¹/₂gt²

2h = gt²

t² = 2h/g

t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 313.6}{9.8} }\\\\t = 8 \ s

4 0
3 years ago
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