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Taya2010 [7]
3 years ago
14

In experimental design: What are the two groups?

Physics
1 answer:
sp2606 [1]3 years ago
7 0

Answer:

The correct answer is : a special type of experimental design where subject divides in two groups according their treatment setting.

Explanation:

A two group is a experimental design two groups are the two different groups of subjects divided by the researcher for comparing the data and result to establish relation in variables.

In normal case, one of the two groups one is a group of subjects who get treatment known as experiment or treatment group while other group is known as control group without treatment.

Thus, the correct answer is : a special type of experimental design where subject divides in two groups according their treatment setting.

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Inductive charging is used to wirelessly charge electronic devices ranging from toothbrushes to cell phones. Suppose the base un
statuscvo [17]

The time required (in s) for the magnetic field to decrease to zero from its maximum value is 1.2 x 10⁻⁶ s.

<h3>Faraday's law of electromagnetic induction</h3>

Faraday's first law of electromagnetic induction states, “Whenever a conductor is placed in a varying magnetic field, an electromotive force is induced.

emf = NdФ/dt

emf = NBA/t

where;

  • N is number of turns of the coil
  • A is area of the coil
  • B is magnetic field
  • t is time

The time required (in s) for the magnetic field to decrease to zero from its maximum value is calculated as follows;

t = NBA/emf

t = (16 x 1.1 x 10⁻³ x 3.75 x 10⁻⁴) / (5.5)

t = 1.2 x 10⁻⁶ s

Thus, the time required (in s) for the magnetic field to decrease to zero from its maximum value is 1.2 x 10⁻⁶ s.

Learn more about magnetic field here: brainly.com/question/7802337

#SPJ1

7 0
2 years ago
The maximum value of the electric field in an electromagnetic wave is 2.0 V/m. What is the maximum value of the magnetic field i
Eddi Din [679]

Answer:

The maximum value of the magnetic field in the given wave is 6.67 nT.

Explanation:

Given;

maximum value of the electric field, E₀ = 2.0 V/m

The maximum value of the magnetic field in the given wave is calculated as;

B_o = \frac{E_o}{c}

where;

c is the speed of light = 3 x 10⁸ m/s

B_o = \frac{E_o}{c} \\\\B_o = \frac{2}{3 \ \times \ 10^8} \\\\B_o = 6.67 \ \times \ 10^{-9} \ T\\\\B_o = 6.67 \ nT

Therefore, the maximum value of the magnetic field in the given wave is 6.67 nT.

7 0
3 years ago
How the forces makes effect on the state of motion of an object ? <br><br> Plz ans fast urgent
Ksju [112]

Answer:

1. It may change the direction of an object in motion.

2. It may cause change in velocity of an object in motion.

Explanation:

1.It may change the direction of an object in motion.

When an object is in motion,an applied force on that object may change its direction.

For example, a sailboat moving eastward, can suddenly change its direction by interaction of a storm wind blowing form the south.

2. It may cause change in velocity of an object in motion .

A force applied to an object in motion can increase or decrease its speed. When the force is applied to the object in motion in the direction of that object, its velocity may increase.

On the other hand, when the force is applied in the opposite direction to the object in motion, its velocity may reduce.

6 0
3 years ago
At a certain location, Earth's magnetic field of 34 µT is horizontal and directed due north. Suppose the net field is zero exact
zheka24 [161]

Answer:

a) I = 13.77 A

b) 0 ° or to the East

Explanation:

Part a

The magnetic field by properties would be 0 at the radius on this case r =8.1 cm.Analyzing the situation the wirde would produce a magnetic field equals in magnitude to the magnetic field on Earth by with the inverse direction.

The formula for the magnetic field due to a wire with current is:

B = \frac{\mu_0 I}{2 \pi r}

In order to have a value of 0 for the magnetic field at the radius then we need to have this balance

B (r=8.1) = B (Earth)

Replacing:

B = \frac{\mu_0 I}{2 \pi r)}= B_{Earth}

Solving from I, from the last equation we got:

I = \frac{2 \pi r B_{earth}}{\mu_0}

I=\frac{2 \pi 0.081 m (34 x 10^{-6} T)}{4 \pi x 10^{-7} Tm/A} = 13.77 A

Part b

We can use the right hand rule for this case.

The magnetic field of the wire would point to the South, because the magnetic field of the earth given points to the North. Based on this the current need's to flow from West to East in order to create a magnetic field pointing to the south, because the current would be perpendicular to the magnetic field created.

8 0
3 years ago
100.0 J of work accelerates a 0.500 kg hockey puck across an ice rink (a frictionless
Olegator [25]

Answer:

d. 100.0 J

Explanation:

To solve this problem we must use the theorem of work and energy conservation. This tells us that the mechanical energy in the final state is equal to the mechanical energy in the initial state plus the work done on a body. In this way we come to the following equation:

E₁ + W₁₋₂ = E₂

where:

E₁ = mechanical energy at state 1. [J] (units of Joules)

E₂ = mechanical energy at state 2. [J]

W₁₋₂ = work done from 1 to 2 [J]

We have to remember that mechanical energy is defined as the sum of potential energy plus kinetic energy.

The energy in the initial state is zero, since there is no movement of the hockey puck before imparting force. E₁ = 0.

The Work on the hockey puck is equal to:

W₁₋₂ = 100 [J]

100 = E₂

Since the ice rink  is horizontal there is no potential energy, there is only kinetic energy

Ek = 100 [J]

It can be said that the work applied on the hockey puck turns into kinetic energy

6 0
3 years ago
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