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Artemon [7]
3 years ago
15

What is the average velocity of a car that travels 50 kilometers due west in 0.50 hour?

Physics
1 answer:
Pie3 years ago
4 0

Average Velocity= displacement/time   Av=50/0.50   Av=100

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State and explain newton second law of motion also describe the concept of force, represent it quantiatively and derive the unit
Molodets [167]

Explanation:

Newton's second law of motion states F=ma which means force is equal to mass multiplied by acceleration which in simple terms means If you give mass force it will accelerate the concept of force in physics is any interaction that when unopposed will change the motion of an object.

8 0
3 years ago
An airplane traveling at 201 m/s makes a turn. What is the smallest radius of the circular path (in km) that the pilot can make
egoroff_w [7]

Answer:

the smallest radius of the circular path is 8.1 km

Explanation:

The computation of the smallest radius of the circular path is given below:

Given that

V = Velocity = 201 m/s

a_c = acceleration = 5 m/s^2

radius = ?

As we know that

a_c = V^2 ÷ r

5 = 201^2 ÷ r

r = 201^2 ÷ 5

= 8,080.2 g

= 8.1 km

Hence, the smallest radius of the circular path is 8.1 km

4 0
2 years ago
What are the factors that keep a satellite in orbit
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8 0
2 years ago
How are the current and resistance related when the voltage if a circuit is constant
sveta [45]

Answer:

They are inversely proportional

Explanation:

3 0
2 years ago
A 0.90- kg mass attached to a vertical spring of force constant 170 N/m oscillates with a maximum speed of 0.20 m/s . Find the f
Alex

Explanation:

Given that,

The mass of the object, m = 0.9 kg

Force constant, k = 170 N/m

Maximum speed of the object, v = 0.2 m/s

Solution,

(a) The angular frequency of the object is given by :

\omega=\sqrt{\dfrac{k}{m}}

\omega=\sqrt{\dfrac{170}{0.9}}

\omega=13.74\ rad/s

The time period is given by :

T=\dfrac{2\pi}{\omega}

T=\dfrac{2\pi}{13.74}

T = 0.45 seconds

(b) The maximum velocity of the object in shm is given by :

v=A\omega

Amplitude,

A=\dfrac{v}{\omega}

A=\dfrac{0.2}{13.74}

A = 0.0145 m

(c) The maximum acceleration of the object is given by :

a=\omega^2A

a=(13.74)^2\times 0.0145

a=2.73\ m/s^2

Therefore, this is the required solution.

3 0
3 years ago
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