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Temka [501]
3 years ago
12

A total of 50 juniors and seniors were given a mathematics test. The 35 juniors attained an average score of 80 while the 15 sen

iors attained an average of 70. What was the average score for all 50 students who took the test?
Mathematics
1 answer:
Alik [6]3 years ago
8 0

Answer:

77

Step-by-step explanation:

Firstly, we need to calculate the total score of the junior students and the total score of the senior students.

The total score of the junior students is 35 * 80 = 2,800

The total score of the senior students is 15 * 70 = 1050

The total score is thus 2,800 + 1,050 = 3,850

The average score of the 50 students is thus 3,850/50 which equals 77

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4 years ago
I need help with question 9
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Answer:

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Step-by-step explanation:

I found the difference in minutes between the given values and the difference in cost between the given values. Between 8 minutes and 25 minutes is 17, and between 25 and 40 is 15 minutes. The difference of $7.25 and $4.36 is $2.89, and the difference between $7.25 and $9.80 is $2.55. I then divided2.89 by 17 and 2.55 by 15 and both resulted in $0.17/minute. I them multiplied 8 minutes by $0.17 toget $1.36. I subtracted that from the cost given for 8 minutes to get $3.00. The $3.00 is the initial charge, or b in slope-intercept form with m=0.17. Plug in 60 for x to find the cost of an hour.

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4 years ago
Find area of blue shaded region
RUDIKE [14]

Answer:

\approx \: 7.33 \:  {cm}^{2}

Step-by-step explanation:

Area of the blue shaded region

=  \frac{ \theta}{360 \degree}  \times \pi r_1^2  - \frac{ \theta}{360 \degree}  \times \pi r_2^2  \\  \\  =   \frac{ \pi\theta}{360 \degree} ( r_1^2 - r_2^2) \\  \\ ( r_1 = 4 \: cm, \:  \:  r_2 = 3\: cm, \:  \:  \theta = 120 \degree) \\  \\ =   \frac{ 3.14 \times 120 \degree}{360 \degree} ( 4^2 - 3^2) \\  \\  =   \frac{ 3.14 }{3}  \times 7 \\  \\  =  \frac{21.98}{3}  \\  \\  = 7.32666667 \\  \\  \approx \: 7.33 \:  {cm}^{2}

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3 years ago
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