How do you write (10, -6) and (-2, -6) as an equation
1 answer:
Answer:
y=-6
Step-by-step explanation:
Method 1:
Both the y coordinates of the points are the same and the x coordinates are distinct.
Therefore the straight line passing through the point is parallel to X-axis.
The common y coordinate is -6, therefore the line equation is y=-6.
Method 2:
We will solve it using general line equation
(y-y1)=()(x-x1)
where (x1,y1) and (x2,y2) are the 2 points.
- (y+6)=(
)(x+2)
- (y+6)=0
- y=-6
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Answer:
Step-by-step explanation:
p = Product of all odd integers between 500 an 598. So,
p = 501 x 503 x 505 ... x 595 x 597
q = Product of all odd integers between 500 and 602. So,
q = 501 x 503 x 505 ... x 595 x 597 x 599 x 601
From the above relations, we can see that q is equal to p multiplied by 599 and 601. i.e.
q = p x 599 x 601
or,
We need to evaluate 1p + 1q in terms of q. Using the value of p from above expression, we get:
Answer:
Step-by-step explanation:
The coordinates are (0,9) and (-8,-4)
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D =
D =
D =
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