3 years ago

How do you write (10, -6) and (-2, -6) as an equation

Mathematics

1 answer:

Paraphin [41]3 years ago

4 0

Answer:

y=-6

Step-by-step explanation:

Method 1:

Both the y coordinates of the points are the same and the x coordinates are distinct.

Therefore the straight line passing through the point is parallel to X-axis.

The common y coordinate is -6, therefore the line equation is y=-6.

Method 2:

We will solve it using general line equation

(y-y1)=( $\frac{y2-y1}{x2-x1}$ )(x-x1)

where (x1,y1) and (x2,y2) are the 2 points.

(y+6)=( $\frac{-6+6}{10+2}$ )(x+2)

(y+6)=0

y=-6

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Line $\ell_1$ is horizontal and passes through $(1,1)$. Line $\ell_2$ is vertical and passes through $(2,2)$. Find the point of

borishaifa [10]

Answer:

(2,1)

Step by step explanation:

Please find the attachment.

We have been given that line $l_1$ is horizontal and passes through point (1,1). Line $l_2$ is vertical and passes through point (2,2). We are asked to find point of intersection of line $l_1$ and line $l_2$ .

Line $l_1$ is a horizontal line so y-coordinate will be 1 for any value of x. Line $l_2$ is a vertical line, so x-coordinate will be 2 for any value of y.

Therefore, intersection point of both lines will include x-coordinate of line $l_2$ and y-coordinate of line $l_1$ that is (2,1).