6^(8x) = 4
log 6^(8x) = log 4
8x log 6 = log 4
x = log 4 / 8log 6 = 0.10 to two decimal places.
Answer:
p-q= -4
p=q-4
x^2 + px + q=0
=> x^2 + (q-4)x + q = 0
d= b^2-4ac
=(q-4)^2 - 4(1)(q)
= q^2 + 16 -8q - 4q
=q^2 -12q+16
given that D=16
q^2 -12q+16 = 16
=> q^2 -12q = 0
=> q^2 = 12q
=> q = 12q/q
=> q= 12
Therefore the value of q is 12 and the value of p is q-4 = 12-4= 8
Hope you understood............
Answer:
D .8
Step-by-step explanation:
hypotenuse (h) = 10
base (b) = 6
perpendicular (p) = a= ?
We know by using Pythagoras theorem we get
p = √ h² - b²
a = √ 10² - 6²
a = √ 64
a = 8
Hope it will help :)
Subtract 6 which leaves u with -3p=-18 then divide by three on both sides to get p=6
