1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iVinArrow [24]
3 years ago
5

Write a program named CountVowelsModularized that passes a string to a method that returns the number of vowels in the string.

Computers and Technology
1 answer:
KengaRu [80]3 years ago
7 0

Answer:

<em>import java.util.Scanner;</em>

<em>public class CountVowelsModularized {</em>

<em>    public static void main(String[] args) {</em>

<em>        Scanner in = new Scanner (System.in);</em>

//Prompt user to enter a string, receive it and assign to a variable<em>        </em>

<em>System.out.println("Enter a string Value");</em>

<em>        String word =in.nextLine();</em>

//Calling the method numVowels and passing the string

<em>        System.out.println("The Number of vowels are " +numVowels(word.toLowerCase()));</em>

<em>    }</em>

<em>}</em>

The method definition and complete program is given in the explanation section<em> </em>

Explanation:

<em>import java.util.Scanner;</em>

<em>public class CountVowelsModularized {</em>

<em>    public static void main(String[] args) {</em>

<em>        Scanner in = new Scanner (System.in);</em>

<em>        System.out.println("Enter a string Value");</em>

<em>        String word =in.nextLine();</em>

<em />

<em>        System.out.println("The Number of vowels are " +numVowels(word.toLowerCase()));</em>

<em>    }</em>

<em>    public static int numVowels(String string) {</em>

<em>        int counter = 0;</em>

<em>        for (int i = 0; i < string.length(); i++) {</em>

<em>            if (string.charAt(i) == 'a' || string.charAt(i) == 'e' || string.charAt(i) == 'i'</em>

<em>                    || string.charAt(i) == 'o' || string.charAt(i) == 'u') {</em>

<em>                counter++;</em>

<em>            }</em>

<em>        }</em>

<em>        return counter;</em>

<em>    }</em>

<em>}</em>

You might be interested in
________ is the process of translating a task into a series of commands that a computer will use to perform the task.
IgorC [24]
Programming 
It can also be described as Reverse Engineering 
7 0
4 years ago
Adam is using the software development life cycle to create a new game. He made an outline of what functionality the game will r
Olin [163]

Answer:

Write pseudocode and create a mock-up of how the game will work and look

Explanation:

Since in the question it is mentioned that Adam wants to develop a new game for this he made an outline with respect to game functions needed, time period, people who help him.

After that, he writes the pseudocode i.e a programming language and then develops a model i.e mock up that reflects the working of the game and its look so that he would get to know how much work is pending.

3 0
3 years ago
Output each floating-point value with two digits after the decimal point, which can be achieved as follows:
sdas [7]

Answer:

The modified program in Python is as follows:

import math

paint_colors = {'red': 35,'blue': 25,'green': 23}

wall_height = int(input('Enter wall height (feet):\n'))

wall_width = int(input('Enter wall width (feet):\n'))

area = wall_height*wall_width

print('Wall area:',area,'square feet')

paint_needed = area/350.0

print('Paint needed: {:.2f} gallons'.format(paint_needed))

print('Cans needed:',round(paint_needed),'can(s)')

color = input("Choose a color to paint the wall: ")

print("Cost of purchasing", color, "paint: $",paint_colors[color])

Explanation:

The italicized are given from the question [unchanged]

<em>import math</em>

<em> paint_colors = {'red': 35,'blue': 25,'green': 23} </em>

<em>wall_height = int(input('Enter wall height (feet):\n')) </em>

This gets input for width

wall_width = int(input('Enter wall width (feet):\n'))

Calculate the wall area

area = wall_height*wall_width

Print the calculated wall area

print('Wall area:',area,'square feet')

Calculate the amount of paint needed

paint_needed = area/350.0

Print the amount of paint needed to 2 decimal places

print('Paint needed: {:.2f} gallons'.format(paint_needed))

Print the amount of can needed to nearest integer

print('Cans needed:',round(paint_needed),'can(s)')

Prompt user for color of paint [here, we assume the user input is correct]

color = input("Choose a color to paint the wall: ")

Prints the corresponding amount for the color

print("Cost of purchasing", color, "paint: $",paint_colors[color])

3 0
3 years ago
Assume that a large number of consecutive IP addresses are available starting at 198.16.0.0 and suppose that two organizations,
Fiesta28 [93]

Answer & Explanation:

An IP version 4 address is of the form w.x.y.z/s

where s = subnet mask

w = first 8 bit field, x = 2nd 8 bit field, y = 3rd 8 bit field, and z = 4th 8 bit field

each field has 256 decimal equivalent. that is

binary                                        denary or decimal

11111111      =        2⁸      =             256

w.x.y.z represents

in binary

11111111.11111111.11111111.11111111

in denary

255.255.255.255

note that 255 = 2⁸ - 1 = no of valid hosts/addresses

there are classes of addresses, that is

class A = w.0.0.0 example 10.0.0.0

class B = w.x.0.0 example 172.16.0.0

class C = w.x.y.0 example 198.16.8.1

where w, x, y, z could take numbers from 1 to 255

Now in the question

we were given the ip address : 198.16.0.0 (class B)

address of quantity 4000, 2000, 8000 is possible with a subnet mask of type

255.255.0.0 (denary) or

11111111.11111111.00000000.00000000(binary) where /s =  /16 That is no of 1s

In a VLSM (Variable Length Subnet Mask)

Step 1

we convert the number of host/addresses for company A to binary

4000 = 111110100000 = 12 bit

step 2 (subnet mask)

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11110000.000000                /20

now we have added 4 1s in the 3rd field to reserve 12 0s

<u><em>subnet mask: 255.255.</em></u><u><em>16.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1       1      </em></u><u><em> 1 </em></u><u><em>      1     1     1     1</em></u>

<u><em>128  64     32    </em></u><u><em>16</em></u><u><em>    8    4     2    1</em></u>

step 3

in the ip network address: 198.16.0.0/19 <em>(subnet representation)</em> we increment this using 16

that is 16 is added to the 3rd field as follows

That means the ist Valid Ip address starts from

          Ist valid Ip add: 198.16.0.1 - 198.16.15.255(last valid IP address)

Company B starts<u><em>+16: 198.16.</em></u><u><em>16</em></u><u><em>.0 - 198.16.31.255</em></u>

<u><em>                   +16: 198.16.</em></u><u><em>32</em></u><u><em>.0- 198.16.47.255 et</em></u>c

we repeat the steps for other companies as follows

Company B

Step 1

we convert the number of host/addresses for company B to binary

2000 = 11111010000 = 11 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 11 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11111000.000000                /21

now we have added 5 1s in the third field to reserve 11 0s

<u><em>subnet mask: 255.255.</em></u><u><em>8.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1       1       1       </em></u><u><em>1 </em></u><u><em>    1     1     1</em></u>

<u><em>128  64     32    16    </em></u><u><em>8 </em></u><u><em>   4     2    1</em></u>

Step 3

Starting from after the last valid Ip address for company A

in the ip network address: 198.16.16.0/21 (<em>subnet representation</em>) we increment this using 8

That means the ist Valid Ip address starts from

           Ist valid Ip add: 198.16.16.1 - 198.16.23.255(last valid IP address)

Company C starts <u><em>+16: 198.16.</em></u><u><em>24</em></u><u><em>.0- 198.16.31.255</em></u>

<em>                             </em><u><em> +16: 198.16.</em></u><u><em>32</em></u><u><em>.0- 198.16.112.255 et</em></u>c

Company C

Step 1

we convert the number of host/addresses for company C to binary

4000 = 111110100000 = 12 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11110000.000000                /20

now we have added 4 1s in the 3rd field to reserve 12 0s

<u><em>subnet mask: 255.255.</em></u><u><em>16.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1       1       1       1     1     1     1</em></u>

<u><em>128  64     32    16    8    4     2    1</em></u>

Step 3

Starting from after the last valid ip address for company B

in the ip network address: 198.16.24.0/20 (subnet representation) we increment this using 16

That means the ist Valid Ip address starts from

           Ist valid Ip add: 198.16.24.1 - 198.16.39.255(last valid IP address)

Company C starts <u><em>+16: 198.16.40.0- 198.16.55.255</em></u>

<em>                          </em><u><em>    +16: 198.16.56.0- 198.16.71.255 et</em></u>c

Company D

Step 1

we convert the number of host/addresses for company D to binary

8000 = 1111101000000 = 13 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 13 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11100000.000000                /19

now we have added 3 1s in the 3rd field to reserve 13 0s

<u><em>subnet mask: 255.255.</em></u><u><em>32.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1      </em></u><u><em> 1 </em></u><u><em>      1       1     1     1     1</em></u>

<u><em>128  64     </em></u><u><em>32  </em></u><u><em>  16    8    4     2    1</em></u>

Step 3

Starting from after the last valid ip address for company C

in the ip network address: 198.16.40.0/20 (subnet representation) we increment this using 32

That means the ist Valid Ip address starts from

           Ist valid Ip add: 198.16.40.1 - 198.16.71.255(last valid IP address)

Company C starts <u><em>+16: 198.16.72.0- 198.16.103.255</em></u>

<em>                          </em><u><em>    +16: 198.16.104.0- 198.16.136.255 et</em></u>c

5 0
3 years ago
A signal travels from point A to point B. At point A, the signal power is 100 W. At point B, the power is 90 W. What is the atte
11Alexandr11 [23.1K]

Answer:

Attenuation = 0.458\ db

Explanation:

Given

Power at point A = 100W

Power at point B = 90W

Required

Determine the attenuation in decibels

Attenuation is calculated using the following formula

Attenuation = 10Log_{10}\frac{P_s}{P_d}

Where P_s = Power\ Input and P_d  = Power\ output

P_s = 100W

P_d = 90W

Substitute these values in the given formula

Attenuation = 10Log_{10}\frac{P_s}{P_d}

Attenuation = 10Log_{10}\frac{100}{90}

Attenuation = 10 * 0.04575749056

Attenuation = 0.4575749056

Attenuation = 0.458\ db <em>(Approximated)</em>

7 0
3 years ago
Other questions:
  • An example of hardware is a _____. database spreadsheet monitor program used to enhance photos
    13·2 answers
  • the type() function in python does what when you give it an object. returns the last keystrokes from the user. fill the object w
    9·1 answer
  • Click to visit W3Schools.com
    14·2 answers
  • Recall the problem of finding the number of inversions. As in the text, we are given a sequence of n numbers a1, . . . , an, whi
    8·1 answer
  • ________ programming is a method of writing software that centers on the actions that take place in a program.
    8·1 answer
  • You want to divide the value in cell D3 by the value in cell E3. Which formula should you use?
    11·2 answers
  • You have just installed a new NIC in your PC to replace the old one that had started malfunctioning. What additional software mu
    15·1 answer
  • When a climbing distance of __________, landing platforms must be in place every __________ feet. Platforms will be offset from
    12·1 answer
  • Witch icon allows you to see paragraph formatting feature
    6·1 answer
  • X = 9 % 2if (x == 1):  print ("ONE")else:  print ("TWO")
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!