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sasho [114]
3 years ago
14

Given the equation 2CH4 S8 --> 2CS2 4H2S Calculate the moles of H2S produced when 1.5 mol S8 is used.

Chemistry
1 answer:
mafiozo [28]3 years ago
8 0

Answer:

6.0 moles of H₂S are produced.

Explanation:

Let's consider the following balanced equation.

2 CH₄ + S₈ → 2 CS₂ +  4 H₂S

The molar ratio of S₈ to H₂S is 1 mol S₈: 4 mol H₂S. The moles of H₂S produced when 1.5 mol of S₈ react are:

1.5 mol S₈ × (4 mol H₂S/ 1 mol S₈) = 6.0 mol H₂S

6.0 moles of H₂S are produced, when 1.5 mol of S₈ react.

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[H+] for HClO(this is a weak acid so it requires an I.C.E. table to solve):


(I=initial amount. C=change in amount. E= amount at equilibrium.)
I.C.E. table
HClO. H2O. >>> H3O+ ClO4-
I. 0.100M. N/A. 0. 0
C. -x. N/A. +x. +x
E. 0.1-x. N/A. x. x.
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(0.1-x)(2.9×10^-8) = x^2
(3.0×10^-9) - ((2.9×10^-8)x) = x^2

x^2+(2.9×10^-8)x-(3×10^-9)

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plug those values into the quadratic formula:

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I got x= 0.000053837

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[H+] for 0.100 M HClO4:
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