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3 years ago

Given the equation 2CH4 S8 --> 2CS2 4H2S Calculate the moles of H2S produced when 1.5 mol S8 is used.

Chemistry

1 answer:

mafiozo [28]3 years ago

8 0

Answer:

6.0 moles of H₂S are produced.

Explanation:

Let's consider the following balanced equation.

2 CH₄ + S₈ → 2 CS₂ + 4 H₂S

The molar ratio of S₈ to H₂S is 1 mol S₈: 4 mol H₂S. The moles of H₂S produced when 1.5 mol of S₈ react are:

1.5 mol S₈ × (4 mol H₂S/ 1 mol S₈) = 6.0 mol H₂S

6.0 moles of H₂S are produced, when 1.5 mol of S₈ react.

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Answer:

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Explanation:

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$3.30(O_{2} moles)-0.85(etOHmoles)*\frac{3(O_{2} moles)}{1(etOHmoles)} =0.75O_{2} moles$

Calculate the number of moles of CO2 and water considering the same:

$0.85(etOHmoles)*\frac{3(H_{2}Omoles)}{1(etOHmoles)}=2.55(H_{2}Omoles)$

$0.85(etOHmoles)*\frac{2(CO_{2}moles)}{1(etOHmoles)}=1.7(CO_{2}moles)$

The total number of moles at the reactor output would be:

$N=1.7(CO2)+12.414(N2)+2.55(H2O)+0.75(O2)\\ N=17.414(Dry-air-moles)$

So, the oxygen mole fraction would be:

$y_{O_{2}}=\frac{0.75}{17.414}=0.0430=4.3$ %

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