Answer:
x+4= -2+4
x+4 = 2
Step-by-step explanation:
Answer:
a. 53.4
b. 24.4
Step-by-step explanation:
a+j=77.8
j=a-29
a+j=77.8
-a+j=-29
2j=48.8
j=24.4
a+24.4=78.8
a=53.4
Answer:

Step-by-step explanation:
We are given that A rose garden can be planted for $4000.
The marginal cost of growing a rose is estimated to $0.30,
Let x be the number of roses
So, Marginal cost of growing x roses = 
Total cost = 
So, Cost function :
---A
Now we are given that the total revenue from selling 500 roses is estimated to $875
So, Marginal revenue = 
Marginal revenue = 
Marginal revenue =
Marginal revenue for x roses = 
So, Revenue function =
----B
Profit = Revenue - Cost

---C
Now Plot A , B and C on Graph
-- Green
-- Purple
--- Black
Refer the attached graph
7.71 feet is your answer.
Answer:
<h2>
![7 \sqrt[3]{2x} - 6 \sqrt[3]{2x} - 6x](https://tex.z-dn.net/?f=7%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%206%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%206x)
</h2>
Solution,
![7( \sqrt[3]{2x} ) - 3( \sqrt[3]{16x} ) - 3( \sqrt[3]{8x} ) \\ = 7 \sqrt[3]{2x} - 3 \times ( \sqrt[3]{2 \times 2 \times 2 \times 2x} - 3 \times \sqrt[3]{2 \times 2 \times 2x} \\ = 7 \sqrt[3]{2x} - 3 \times (2 \sqrt[3]{2} x) - 3 \times 2x \\ = 7 \sqrt[3]{2x} - 3 \times 2 \times \sqrt[3]{2x} - 3 \times 2x \\ = 7 \sqrt[3]{2x} - 6 \sqrt[3]{2x} - 6x](https://tex.z-dn.net/?f=7%28%20%5Csqrt%5B3%5D%7B2x%7D%20%29%20-%203%28%20%5Csqrt%5B3%5D%7B16x%7D%20%29%20-%203%28%20%5Csqrt%5B3%5D%7B8x%7D%20%29%20%5C%5C%20%20%3D%207%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%203%20%5Ctimes%20%28%20%5Csqrt%5B3%5D%7B2%20%5Ctimes%202%20%5Ctimes%202%20%5Ctimes%202x%7D%20%20-%203%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B2%20%5Ctimes%202%20%5Ctimes%202x%7D%20%20%5C%5C%20%20%3D%207%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%203%20%5Ctimes%20%282%20%5Csqrt%5B3%5D%7B2%7D%20x%29%20-%203%20%5Ctimes%202x%20%5C%5C%20%20%3D%207%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%203%20%5Ctimes%202%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%203%20%5Ctimes%202x%20%5C%5C%20%20%3D%207%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%206%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%206x)
Hope this helps...
Good luck on your assignment...