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amid [387]
3 years ago
14

What is the slope of (-8,-20) (-7,-10)

Mathematics
1 answer:
Zarrin [17]3 years ago
7 0

Answer:

10

Step-by-step explanation:

Formula for slope: (y2-y1)/(x2-x1)

Plug the numbers in: (-10-(-20))/(-7-(-8))=10/1=10

Slope is 10.

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Which types of triangles can be formed by taking the cross-section of a rectangular prism like the one shown above?
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A.

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A student has a monthly budget of $800. She can spend her budget on two items, X and Y. Each unit of X costs $20 and each unit o
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Check the explanation

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Total utility is the overall satisfaction that a particular consumer received from consuming a given overall quantity of a good or service, To calculate the value of total utility economists utilize the following basic total utility formula: TU = U1 + MU2 + MU3

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3 years ago
What is the Point slope equation
anastassius [24]

Answer:

y - y1 = m(x - x1)

Step-by-step explanation:

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3 0
3 years ago
Find the distance from the origin to the graph of 7x+9y+11=0
Cerrena [4.2K]
One way to do it is with calculus. The distance between any point (x,y)=\left(x,-\dfrac{7x+11}9\right) on the line to the origin is given by

d(x)=\sqrt{x^2+\left(-\dfrac{7x+11}9\right)^2}=\dfrac{\sqrt{130x^2+154x+121}}9

Now, both d(x) and d(x)^2 attain their respective extrema at the same critical points, so we can work with the latter and apply the derivative test to that.

d(x)^2=\dfrac{130x^2+154x+121}{81}\implies\dfrac{\mathrm dd(x)^2}{\mathrm dx}=\dfrac{260}{81}x+\dfrac{154}{81}

Solving for (d(x)^2)'=0, you find a critical point of x=-\dfrac{77}{130}.

Next, check the concavity of the squared distance to verify that a minimum occurs at this value. If the second derivative is positive, then the critical point is the site of a minimum.

You have

\dfrac{\mathrm d^2d(x)^2}{\mathrm dx^2}=\dfrac{260}{81}>0

so indeed, a minimum occurs at x=-\dfrac{77}{130}.

The minimum distance is then

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4 0
3 years ago
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