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Vesna [10]
4 years ago
11

If a star's radial velocity is -50 km/s, the frequency of its light would appear to be ______ (higher or lower) than its true fr

equency. We usually say that the star's wavelength is __________ (blue or red) shifted.
Physics
1 answer:
Phoenix [80]4 years ago
3 0

Answer: If a star's radial velocity is -50 km/s, the frequency of its light would appear to be higher than its true frequency. We usually say that the star's wavelength is blue shifted.

Explanation:

Radial velocity is defined as the velocity of how an object is seen by the axis of a circle.

Then, if the radial velocity is -50km/s, this means that the radius is decreasing, and then that the star is coming towards the viewer.

as the star is coming towards the viewer, we will see a shorter wavelength, which implies that the frequency would appear to be bigger as it really is.

and this is called a blue shift, because the blue light is the visible light with the biggest frequency, while the red light is the visible light with the smallest frequency, then we have:

If a star's radial velocity is -50 km/s, the frequency of its light would appear to be higher than its true frequency. We usually say that the star's wavelength is blue shifted.

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Astrology, that unlikely and vague pseudoscience, makes much of the position of the planets at the moment of one’s birth. The on
astraxan [27]

Answer: (a)F=7(10)^{-7}N

              (b)F=1.344(10)^{-6}N  

              (c) The force of Jupiter on the baby is slightly greater than the the force of the father on the baby.

Explanation:

According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:

F=G\frac{m_{1}m_{2}}{r^2}   (1)

Where:

F is the module of the force exerted between both bodies

G is the universal gravitation constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}

m_{1} and m_{2} are the masses of both bodies.

r is the distance between both bodies

Knowing this, let's begin with the answers:

<h2 /><h2>(a) Gravitational force Father exertes on baby</h2>

Using equation (1) and taking into account the mass of the father m_{1}=100kg, the mass of the baby m_{2}=4.20kg and the distance between them r=0.2m, the force F_{F}  exerted by the father is:

F_{F}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(100kg)(4.20kg)}{(0.2m)^2}   (2)

F_{F}=0.0000007N=7(10)^{-7}N   (3)

<h2>(b) Gravitational force Jupiter exertes on baby</h2>

Using again equation (1) but this time taking into account the mass of Jupiter m_{J}=1.898(10)^{27}kg, the mass of the baby m_{2}=4.20kg and the distance between Jupiter and Earth (where the baby is) r_{E}=6.29(10)^{11}m, the force F_{J}  exerted by the Jupiter is:

F_{J}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(1.898(10)^{27}kg)(4.20kg)}{(6.29(10)^{11}m)^2}   (4)

F_{J}=0.000001344N=1.344(10)^{-6}N   (5)

<h2>(c) Comparison</h2>

Now, comparing both forces:

F_{J}=0.000001344N=1.344(10)^{-6}N   and F_{F}=0.0000007N=7(10)^{-7}N  we can see F_{J} is greater than F_{F}. However, the difference is quite small as well as the force exerted on the baby.

7 0
3 years ago
A particle moves on a line away from its initial position so that after t hours it is s = 6t2 + 2t miles from its initial positi
docker41 [41]
<span>32 mph
   First, let's calculate the location of the particle at t=1, and t=4
 t=1
 s = 6*t^2 + 2*t
 s = 6*1^2 + 2*1
 s = 6 + 2
 s = 8 t = 4
 s = 6*t^2 + 2*t s = 6*4^2 + 2*4
 s = 6*16 + 8
 s = 96 + 8
 s = 104
   So the particle moved from 8 to 104 over the time period of 1 to 4 hours. And the average velocity is simply the distance moved over the time spent. So:
 avg_vel = (104-8)/(4-1) = 96/3 = 32
   And since the units were miles and hours, that means that the average speed of the particle over the interval [1,4] was 32 miles/hour, or 32 mph.</span>
6 0
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alexdok [17]

Answer:

Gamma radiation.

Explanation:

Electromagnetic waves are waves produced with respect to the interaction of electric field and magnetic field. They can be arranged with respect to their increasing or decreasing wavelength to form a pattern called electromagnetic spectrum.

Gamma radiation can be used for sterilization purpose due to the fact that it has a relatively high amount of energy, and do not produce any characteristic radiation.

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5 0
4 years ago
Martha designed the model shown below to represent the positions of earth, sun, and moon during tides. the model most likely rep
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