If you walk 3 kilometers in 30 minutes , what is the average speed in kilometers per hour?

A uniform rod is set up so that it can rotate about a perpendicular axis at one of its ends. The length and mass of the rod are

igor_vitrenko [27]

Answer:

0.231 N

Explanation:

To get from rest to angular speed of 6.37 rad/s within 9.87s, the angular acceleration of the rod must be

$\alpha = \frac{\theta}{t} = \frac{6.37}{9.87} = 0.6454 rad/s^2$

If the rod is rotating about a perpendicular axis at one of its end, then it's momentum inertia must be:

$I = \frac{mL^2}{3} = \frac{1.27*0.847^2}{3} = 0.303kgm^2$

According to Newton 2nd law, the torque required to exert on this rod to achieve such angular acceleration is

$T = I\alpha = 0.303*0.6454 = 0.196 Nm$

So the force acting on the other end to generate this torque mush be:

$F = \frac{T}{L} = \frac{0.196}{0.847} = 0.231 N$

4 0

3 years ago

What is the passenger's apparent weight at t=1.0s?

Fittoniya [83]

Answer:

For the complete question provided in explanation, if the elevator moves upward, then the apparent weight will be 1035 N. While for downward motion the apparent weight will be 435 N.

Explanation:

The question is incomplete. The complete question contains a velocity graph provided in the attachment. This is the velocity graph for an elevator having a passenger of 75 kg.

From the slope of graph it is clear that acceleration at t = 1 sec is given as:

Acceleration = a = (4-0)m/s / (1-0)s = 4 m/s^2

Now, there are two cases:

1- Elevator moving up

2- Elevator moving down

For upward motion:

Apparent Weight = m(g + a)

Apparent Weight = (75 kg)(9.8 + 4)m/s^2

Apparent Weight = 1035 N

For downward motion:

Apparent Weight = m(g - a)

Apparent Weight = (75 kg)(9.8 - 4)m/s^2

Apparent Weight = 435 N

4 0

3 years ago

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Dr. West mixes zinc (Zn) and hydrochloric acid (HCl) together in his laboratory. The two chemicals react to form hydrogen gas (H

svp [43]

Answer :

A : hydrogen gas and zinc chloride

4 0

3 years ago

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Una carga positiva de 4 x 10-5 C, se encuentra a 0.05 m de otra carga positiva de 2 x 10-5 C. Calcular la fuerza que se ejerce e

KATRIN_1 [288]

Answer:

La fuerza que se ejerce entre las dos cargas es 2880 N.

Explanation:

La ley de Coulomb indica que los cuerpos cargados sufren una fuerza atractiva o repulsiva al acercarse. La fuerza es atractiva si las cargas son del signo opuesto y repulsión si son del mismo signo. El valor de la fuerza es proporcional al producto del valor de sus cargas e inversamente proporcional al cuadrado de la distancia que los separa. Esto se expresa matemáticamente como:

$F=k*\frac{Q*q}{r^{2} }$

donde:

F es la fuerza eléctrica de atracción o repulsión. Se mide en Newtons (N).
Q y q son los valores de las dos cargas puntuales. Se miden en culombios (C).
r es el valor de la distancia que los separa. Se mide en metros (m).
k es una constante de proporcionalidad llamada constante de la ley de Coulomb.

En este caso:

F= ?
Q= 4*10⁻⁵ C
q= 2*10⁻⁵ C
r= 0.05 m
k= 9*10⁹ $\frac{N*m^{2} }{C^{2} }$

Reemplazando:

$F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{4*10^{-5} C*2*10^{-5}C }{(0.05 m)^{2} }$

F= 2880 N

La fuerza que se ejerce entre las dos cargas es 2880 N.

7 0

3 years ago

Which atoms have the lowest electronegativity?

jek_recluse [69]

Answer: Option A) Atoms to the left on the periodic table

Explanation:

The periodic table has metallic elements on the left side, semi-metal or metalloids in the middle, and nonmetallic elements of the right side.

Since, electronegativity of an atom tells of its power to attract electrons. Metals give off electrons rather than attract electrons like non-metals; thus, metals have the lowest electronegativity (with values less than 2.4 while nonmetal have high electronegativity values above 2.7

Infact, the element with the highest electronegativity is a non-metal (fluorine) while the element with the lowest electronegativity is a metal (potassium)

Thus, metallic atoms located on the left side of the periodic table have the lowest electronegativity

6 0

3 years ago

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