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2 years ago

If you walk 3 kilometers in 30 minutes , what is the average speed in kilometers per hour?

Physics

1 answer:

Pepsi [2]2 years ago

4 0

Answer:

6 km/h

Explanation:

V avg = ∆x/∆t = 3km / 30 min ×(60min/1h) = 3 km× 2 /h = 6 km/h

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1. A 1,000-kg car has 50,000 joules of kinetic energy. What is its speed?

bulgar [2K]

Use KE= 1/2mv^2
So...
50,000=(.5)(1,000)v^2
50,000=500 x v^2
Divide 500 on both sides
100 = v^2
Square root both sides to get rid of v^2
Therefore v = 10 m/s

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3 years ago

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Vitek1552 [10]

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3 years ago

Gold’s natural state has a shape and a define volume that is gold’s natural state

kykrilka [37]

Answer:

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2 years ago

A lumberjack (mass = 110 kg) is standing at rest on one end of a floating log (mass = 206 kg) that is also at rest. The lumberja

Lemur [1.5K]

Answer:

a). The velocity of the first log is -1.65 m/s.

(b). The velocity of the second log is 1.07 m/s.

Explanation:

Given that,

Mass of lumberjack M= 110 kg

Mass of log m= 206 kg

Final velocity = 3.09 m/s

(a). We need to calculate the velocity of the first log just before the lumberjack jumps off

Using conservation of momentum

$Mu_{1}+mu_{2}=Mv_{1}+mv$

Put the value into the formula

$0=110\times3.09+206v$

$v=-\dfrac{110\times3.09}{206}$

$v=-1.65\ m/s$

The velocity of the first log is -1.65 m/s.

(b). If the lumberjack comes to rest relative to the second log

We need to calculate the velocity of the second log

$(M+m)v=Mv_{1}$

$v=\dfrac{Mv_{1}}{M+m}$

Put the value into the formula

$v=\dfrac{110\times3.09}{110+206}$

$v=1.07\ m/s$

The velocity of the second log is 1.07 m/s.

Hence, (a). The velocity of the first log is -1.65 m/s.

(b). The velocity of the second log is 1.07 m/s.

4 0

3 years ago

Could someone help me on #7?

ozzi

i would sat C then the impact is weaker

8 0

3 years ago