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Lana71 [14]
2 years ago
15

In order for maximum work to be done...

Physics
2 answers:
Tju [1.3M]2 years ago
5 0

free lil peezy and drake is kool

Bumek [7]2 years ago
3 0

Answer:

For constant traveled distance and applied forces, apply the for parallel to the direction of the movement.

Explanation:

W = F.d = |F||d|cos(\theta)\\

There are 3 components in the amount of work produced when applying a force to an object.

1. The amount of force applied

2. The distance that the object is traveled

3. The angle between the force vector and the distance vector

  • To get the maximum amount of work for a constant force and distance, the force needs to be along the distance traveled => \theta = 0
  • If the angle and the distance are constant, the only way is to apply a larger force in magnitude
  • If the angle and the force are constant, increasing the distance traveled will result in higher amount of work produced.
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What type of Psychologist was B.F. Skinner?
Sladkaya [172]

Answer:

Behaviorist

Explanation:

BF skinner was big on behaviorism and produced massive amounts of support for operant conditionining. He literally had a Skinner box where he did experiments with animals regarding conditionining .

4 0
2 years ago
(a) Find the frequency of revolution of an electron with an energy of 114 eV in a uniform magnetic field of magnitude 46.7 µT. (
stira [4]

Answer:

(a)  1.3 x 10^6 Hz

(b) 76.73 cm

Explanation:

(a)

the formula for the frequency is given by

f = B q / 2 π m

where, B be the strength of magnetic field, q be the charge on one electron, m is the mass of one electron.

B = 46.7 micro tesla = 46.7 x 10^-6 T

q = 1.6 x 10^-19 C

m = 9.1 x 10^-31 kg

f = (46.7 x 10^-6 x 1.6 x 10^-19) / (2 x 3.14 x 9.1 x 10^-31) = 1.3 x 10^6 Hz

(b) K = 114 eV = 114 x 1.6 x 10^-19 J = 182.4 x 10^-19 J

K = 1/2 mv^2

182.4 x 10^-19 = 0.5 x 9.1 x 10^-31 x v^2

v = 6.3 x 10^6 m/s

r = m v / B q

Where, r be the radius of circular path

r = (9.1 x 10^-31 x 6.3 x 10^6) / (46.7 x 10^-6 x 1.6 x 10^-19)

r = 0.7673 m = 76.73 cm  

5 0
3 years ago
Alarge plate is fabricated from a steel alloy that has a plane strain fracture toughness of 82.4 MPa m1/2. If the plate is expos
Korvikt [17]

Answer:

minimum length of a surface crack is 18.3 mm

Explanation:

Given data

plane strain fracture toughness K = 82.4 MPa m1/2

stress σ = 345 MPa

Y = 1

to find out

the minimum length of a surface crack

solution

we will calculate length by this formula

length = 1/π ( K / σ Y)²

put all value

length = 1/π ( K / σ Y)²

length = 1/π ( 82.4 10^{3/2} / 345× 1)²

length = 18.3 mm

minimum length of a surface crack is 18.3 mm

4 0
2 years ago
The first stage in the GAS model of stress is
Vladimir [108]
<span>The first stage in the Gas model of stress is alarm and mobilization. So the correct option in regards to the given question is option “d”. Hans Selye is the person that evolved this model and he has explained this model in complete details.  He has broken down his model into three stages. The first stage involves alarm and mobilization. The second stage includes resistance. The third and the final stage include the exhaustion stage. These are the stages that an organism goes through to restore back the balance when stress is exerted from outside. </span>


8 0
3 years ago
HELP
dem82 [27]

Answer:

Explanation:

28 / 70 = 0.3857142...  = 0.39 hr

280 / 100 = 2.8 hrs.

(100 - 0) / 10 = 10 m/s²

(60 - 20) / 4 = 10 m/s²

3 0
2 years ago
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