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Lana71 [14]
3 years ago
15

In order for maximum work to be done...

Physics
2 answers:
Tju [1.3M]3 years ago
5 0

free lil peezy and drake is kool

Bumek [7]3 years ago
3 0

Answer:

For constant traveled distance and applied forces, apply the for parallel to the direction of the movement.

Explanation:

W = F.d = |F||d|cos(\theta)\\

There are 3 components in the amount of work produced when applying a force to an object.

1. The amount of force applied

2. The distance that the object is traveled

3. The angle between the force vector and the distance vector

  • To get the maximum amount of work for a constant force and distance, the force needs to be along the distance traveled => \theta = 0
  • If the angle and the distance are constant, the only way is to apply a larger force in magnitude
  • If the angle and the force are constant, increasing the distance traveled will result in higher amount of work produced.
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A glider with mass 0.24 kg sits on a frictionless horizontal air track, connected to a spring of negligible mass with force cons
shepuryov [24]

Answer:

v=2.556m/s

Explanation:

From the conservation of mechanical energy

K_{E1}+U_1=K_{E2}+U_2

\frac{1}{2}m*v_1^2+\frac{1}{2}*K*x_1^2=\frac{1}{2}m*v_2^2+\frac{1}{2}*K*x_2^2

x_2=0.08m

v_1=0 m/s

Solve to velocity v2

m*v_2^2=k*x_1^2-k*x_2^2

v^2=\frac{k}{m}*(x_1^2-x_2^2)

v^2=\frac{5.5N/m}{0.24kg}*(0.54m^2-0.080^2)

v=\sqrt{6.54m^2/s^2}=2.556m/s

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Explanation:

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Answer:

True.

Explanation:

Total internal reflection is bound to occur when light travels from dense medium to less dense.

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