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Allisa [31]
3 years ago
6

According to a college survey, 22% of all students work full time. find the mean for the number of 3) students who work full tim

e in samples of size 16.
Physics
1 answer:
attashe74 [19]3 years ago
3 0

Assuming that the students worldwide are being considered, because of the extremely large population, this can be considered as a binomial distribution. A normal distribution is used most usually as a fair approximation of the binomial. The mean is the expectation, therefore:<span>
E[x] = np = (16)(0.22) = 3.52 
<span>μ = 3.52 </span></span>

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Convert 66.2 mi/h to m/s. 1 mi = 1609 m.<br> Answer in units of m/s.
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Answer:

Explanation:

66.2mi/h to m/s

\frac{1609m}{1mi}×\frac{66.2mi}{1h}×\frac{1h}{60min}×\frac{1min}{60s}

  1. mi will go with mi
  2. h with h
  3. min with min
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\frac{1609*66.2}{60*60}= 29.58772222

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