explain when it might be more efficient to use the percent equation rather than the percent proportion?

1 answer:

3 0

Proportions vs. Percent Equations Two Sides of the Same Coin POD Remember that a proportion deals with the equality of two ratios. Now YOU try it. What is a percent equation? In class problems: Define Percent Equation using p. 456 of your textbook Take a look at this proportion: 12 8 2x+12 24 = Can the 12 and 24 cancel?
<span>Explain. (zoom back out to see the proportion if needed) Is there another way to simplify this problem before cross multiplying? complete with you neighbor and turn in ONE sheet together! Question #2 Question #1 Do you have to use cross products to solve this proportion? Question #3 #4 - SOLVE the proportion TWO different ways! (hint: the book uses a slightly different name for this concept...) FIRST: SECOND: Amount Base % 100 = Convert the proportion below into a percent equation: Percent Equation ...write it down!</span>

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You are making bouquets to sell. You have 60 roses, 84 daisies, and 24 lilies. Each bouquet will have the same number of each ki

laiz [17]

You can make 6 bouquets. Each bouquet will have 10 roses, 14 daisies, and 4 lilies.
The math:
FIND THE GREATEST COMMON FACTOR
60/6=10--->10 ROSES
84/6=14--->14 DAISIES
24/6=4--->4 LILIES

Hope this helped!

7 0

3 years ago

There are 3 red marbles, 5 green marbles, and 2 blue marbles in a jar. Event A is defined as drawing a red marble from the jar o

Anastaziya [24]

P(B/A) is $\frac{5}{9}$ in the simplest form

Step-by-step explanation:

Let us explain how to solve the problem

P(B|A) is called the "Conditional Probability" of B given A
Conditional probability is the probability of one event occurring with some relationship to one or more other events that means event A has already happened, now what is the chance of event B
The formula for conditional probability is P(B|A) = P(A and B)/P(A), where P(A and B) is P(A) . P(B given A occurred)

∵ There are 3 red marbles, 5 green marbles, and 2 blue

marbles in the jar

∴ The total number of the marbles in the jar = 3 + 5 + 2 = 10

∵ Two marbles are drawn from the bag, one after the other without

replacement

- That means red is already occurred when green is happened,

so it is a "Conditional Probability" of green given red

P(B/A) = P(A and B)/P(A)

∵ Event A is defined as drawing a red marble from the jar on

the first draw

∴ P(A) = P(red)

∵ P(red) = $\frac{3}{10}$