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SVEN [57.7K]
3 years ago
10

Which of the following is the value of the expression 3x+7, when x=6

Mathematics
1 answer:
kramer3 years ago
6 0

Answer:

25.

Step-by-step explanation:

3 times 6 is 18.

18 plus 7 is 25.

There's your answer.

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What equation is equal to 6/7. I'm very confused.Can one of you guys please help me? Thank You
Burka [1]
0.85 is equal to 6/7 because you divide six by seven....Hope this helped. 

3 0
3 years ago
What is the product of 1.7 × 10−13 and 3.5 × 1025? 1.8 × 1012 2.06 × 1012 3.5 × 1012 5.95 × 1012
Anuta_ua [19.1K]
Do you have paper and a pen on you this is very simple to workout The first one is 4 and the other one is 3587.5 and the last one is <span>8.0992869</span>
3 0
3 years ago
The volume ( v) of a gas in a container at a constant temperature varies inversely as the pressure (p). If the volume of a gas i
andre [41]
The answer is 12.8 cm³

<span>The volume ( v) of a gas in a container at a constant temperature varies inversely as the pressure (p):
v = k/p
p * v = k  (k - constant)

p1v1 = k
p2v2 = k
So, p1v1 = p2v2

v1 = 24 cm</span>³
p1 = 16 lb
v2 = ?
p2 = 30 lb

24 * 16 = x * 30
384 = x * 30
x = 384 / 30
x = 12.8 cm³
3 0
3 years ago
A consumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips, etc.). While
Murljashka [212]

Answer:

The expected number of appearance defects in a new car  = 0.64

standard deviation = 0.93(approximately)

Step-by-step explanation:

Given -

7% had exactly three, 11% exactly two, and 21% only one defect in cars.

Let X be no of defects in a car

P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21

P(X=0 ) = 1 - .07 - .11 - .21 = 0.61

The expected number of appearance defects in a new car =

E(X) = \nu = = \sum X P(X) =3\times 0.07 + 2\times0.11 + 3\times0.21 + 0\times0.61 = 0.64

\sigma^{2}  = variation of E(X) = \sum (X - \nu) ^{2}P(X) = (3 - 0.64) ^{2}\times0.07 + (2 - 0.64) ^{2}\times0.11 + (1 - 0.64) ^{2}\times0.21 + (0 - 0.64) ^{2}\times0.61

 = (2.36) ^{2}\times0.07 + (1.36) ^{2}\times0.11 + (.36) ^{2}\times0.21 + ( 0.64) ^{2}\times0.61 = 0.8704

standard deviation  =  \sqrt{\sigma^{2}} = \sqrt{0.8704^{2}} = 0.93(approximately)

4 0
3 years ago
Please can someone help thank you
Nitella [24]

Answer:

it would be 36-45 and 56-64

5 0
3 years ago
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