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Lubov Fominskaja [6]
3 years ago
14

How are project deliverables determined?

Engineering
2 answers:
Greeley [361]3 years ago
7 0

Answer:

The essence including its problem is listed throughout the clarification section following.

Explanation:

Projects build deliverable that seem to be the products of the venture or indeed the implementation of the project. This ensures that perhaps the agile methodology may be as broad as either the goal of the study itself as well as the coverage that would be part of a much larger venture.

For every other production to have been marked as "deliverable" within the same project, this should satisfy a few eligibility requirements:

  • It should be within the development of the work.
  • The interested parties-external or internal-must consent to the above. This is perhaps the product of hard effort.

So that the above seems to be the right answer.

Alex17521 [72]3 years ago
7 0
It is determined by:

For any output to be classified as a “deliverable” within a project, it has to meet a few criteria: It must be within the scope of the project. Stakeholders external or internal must agree to it. It must be the result of deliberate work.
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Give me an A please!!!¡!!!!¡
Andrei [34K]

Answer:

I am in 6th grade why am i in high school things.

Explanation:

8 0
3 years ago
The given family of functions is the general solution of the differential equation on the indicated interval.Find a member of th
Alja [10]

Answer:

Explanation:

y'''+y=0---(i)

General solution

y=c_1e^o^x+c_2\cos x +c_3 \sin x\\\\\Rightarrow y=c_1+c_2 \cos x+c_3 \sin x---(ii)\\\\y(\pi)=0\\\\\Rightarrow 0=c_1+c_2\cos (\pi)+c_3\sin (\pi)\\\\\Rightarrow c_1-c_2=0\\\\c_1=c_2---(iii)

y'=-c_2\cos x+c_3\cosx\\\\y'(\pi)=2\\\\\Rightarrow2=-c_2\sin(\pi)+c_3\cos(\pi)\\\\\Rightarrow-c_2(0)+c_3(-1)=2\\\\\Rightarrow c_3=-2\\\\y''-c_2\cos x -c_3\sin x\\\\y''(\pi)=-1\\\\\Rightarrow-1=-c_2 \cos (\pi)=c_3\sin(\pi)\\\\\Rightarrow-1=c_2-0\\\\\Rightarrow c_2=-1

in equation (iii)

c_1=c_2=-1

Therefore,

\large\boxed{y=-1-\cos x-2\sin x}

5 0
3 years ago
For this question you must write a java class called Rectangle and a client class called RectangleClient. The partial Rectangle
Alex Ar [27]

Answer:

Java program is given below. You can get .class after you execute java programs, You can attach those files along with .java classes given , Those .class files are generated ones.

Explanation:

//Rectangle.java class

public class Rectangle {

private int x;

private int y;

private int width;

private int height;

// constructs a new Rectangle with the given x,y, width, and height

public Rectangle(int x, int y, int w, int h)

{

this.x=x;

this.y=y;

this.width=w;

this.height=h;

}

// returns the fields' values

public int getX()

{

return x;

}

public int getY()

{

return y;

}

public int getWidth()

{

return width;

}

public int getHeight()

{

return height;

}

// returns a string such as “Coordinate is (5,12) and dimension is 4x8” where 4 is width and 8 is height. public String toString()

public String toString()

{

String str="";

//add x coordidate , y-coordinate , width, height and area to str and return

str+="Coordinate is ("+x+","+y+")";

str+=" and dimension is : "+width+"x"+height;

str+=" Area is "+(width*height);

return str;

}

public void changeSize(int w,int h)

{

width=w;

height=h;

}

}

======================

//main.java

class Main {

public static void main(String[] args) {

//System.out.println("Hello world!");

//create an object of class Rectangle

Rectangle rect=new Rectangle(5,12,4,8);

//print info of rect using toString method

System.out.println(rect.toString());

//chamge width and height

rect.changeSize(3,10);

//print info of rect using toString method

System.out.println(rect.toString());

}

}

==========================================================================================

//Output

Coordinate is (5,12) and dimension is : 4x8 Area is 32

Coordinate is (5,12) and dimension is : 3x10 Area is 30

========================================================================================

6 0
3 years ago
When you are climbing a hill on a bike with different speeds, why does it seem like you are pedaling a lot to cover a short dist
ololo11 [35]

It seems like your pedaling a lot because it takes more energy and is way slower than a regular road. It you switch to the higher gear it will make you go slower because it is made for going down hill or going high speeds and a lower gear will help you more cause its easier and it will make it go faster.

5 0
3 years ago
1. What affects the weight of an airplane?<br> a. Mass<br> b. Matter<br> c. Materials<br> d. Speed
BARSIC [14]
Mass affects the weight of an airplane because everything has mass
5 0
1 year ago
Read 2 more answers
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