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kvv77 [185]
3 years ago
10

What is the command in the java script that receives data from the user

Engineering
1 answer:
solmaris [256]3 years ago
6 0

Answer:ummmmmmmmmmmm

Explanation:

Uuaysgggahanwnyecegvxg

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What does snow fall from?
Klio2033 [76]

Answer:

Clouds

Explanation:

It is created by trapped dust and water.

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3 years ago
Heres a question that needs to be answered fast im running out of time
earnstyle [38]

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9

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What is the difference between an arch and a dome?
bonufazy [111]
This is an arch, its basically a half circle attach to a rectangle, you could also think of it as an upside down U. A dome is a Sphere with the inside hollowed out.

1 difference is a dome is a 3 dimensional shape while an arch is normally not. Or that a dome is the complete shape with a arch act as it’s diameter.

4 0
2 years ago
Select three ways an engineer can create a view of a design.
Angelina_Jolie [31]

Sketching projection

  • Sketching will give the brief planning of the engineering work to be done so it's important

Isometric projection

  • Yes doing a work in 3D factor out the mistakes which can be optimised

Third angle projection:-

  • Viewing angles matter a lot
  • So it will help the engineer to make it perfect from all angles
5 0
2 years ago
A fluid with a relative density of 0.9 flows in a pipe which is 12 m long and lies at an angle of 60° to the horizontal At the t
Minchanka [31]

Answer:

Q=7.3\times 10^{-3} m^3/s

Explanation:

Given that

At topd_2=30 mm,P_2=860 KPa ,P_1=1000 KPa,d_1=85 mm

\rho =900\dfrac{Kg}{m^3}

We know that

\dfrac{P_1}{\rho g}+\dfrac{V_1^2}{2g}+Z_1=\dfrac{P_2}{\rho g}+\dfrac{V_2^2}{2g}+Z_2

A_1V_1=A_2V_2

\frac{V_1}{V_2}=\left(\dfrac{d_2}{d_1}\right)^2

\frac{V_1}{V_2}=\left(\dfrac{30}{85}\right)^2

V_2=8.02V_1

Z_2=12 sin60^{\circ}

\dfrac{1000\times 1000}{900\times 9.81}+\dfrac{V_1^2}{2\times 9.81}+0=\dfrac{860\times 1000}{900\times 9.81 }+\dfrac{V_2^2}{2\times 9.81}+12 sin60^{\circ}

So V_1=1.30m/s

We know that flow rate Q=AV

Q=A_1V_1

By putting the values

A_1=\dfrac{\pi}{4}d^2

Q=7.3\times 10^{-3} m^3/s

To find the flow rate we do not need the direction of flow,because we are just doing balancing of energy at inlet and at the exits of pipe.

4 0
3 years ago
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