All categories

3 years ago

What is the command in the java script that receives data from the user

Engineering

1 answer:

solmaris [256]3 years ago

6 0

Answer:ummmmmmmmmmmm

Explanation:

Uuaysgggahanwnyecegvxg

You might be interested in

The value of Rth is *

Vladimir79 [104]

Johnjjjjjjhhhhhhhhjjjjjjjjjjj

4 0

2 years ago

6. Find the heat flow in 24 hours through a refrigerator door 30.0" x 58.0" insulated with cellulose fiber 2.0" thick. The tempe

Ilia_Sergeevich [38]

Answer:

The heat flow in 24 hours through the refrigerator door is approximately 1,608.57 BTU

Explanation:

The given parameters are;

The duration of the heat transfer, t = 24 hours = 86,400 seconds

The area of the refrigerator door, A = 30.0" × 58.0" = 1,740 in.² = 1.122578 m²

The material of the insulator in the door = Cellulose fiber

The thickness of the insulator in the door, d = 2.0" = 0.0508 m

The temperature inside the fridge = 38° F = 276.4833 K

The temperature of the room = 78°F = 298.7056 K

The thermal conductivity of cellulose fiber = 0.040 W/(m·K)

By Fourier's law, the heat flow through a by conduction material is given by the following formula;

$\dfrac{Q}{t} = \dfrac{k \cdot A \cdot (T_2 - T_1) }{d}$

$Q = \dfrac{k \cdot A \cdot (T_2 - T_1) }{d} \times t$

Therefore, we have;

$Q = \dfrac{0.04 \times 1.122578 \times (298.7056 - 276.4833 ) }{0.0508} \times 86,400 =1,697,131.73522$

The heat flow in 24 hours through the refrigerator door, Q = 1,697,131.73522 J = 1,608.5705140685 BTU

7 0

2 years ago

I'm a grandma my Samuel needs to be tough in math what do I do

Sedbober [7]

Well you could always do what Hispanics do and repeat the question 2-3 times while yelling till they finally answer

7 0

3 years ago

Read 2 more answers

A student proposes a complex design for a steam power plant with a high efficiency. The power plant has several turbines, pumps,

masha68 [24]

Answer:

(a). max possible efficiency = 55.62%

(b). max power output = = 133.5 MW

Explanation:

From the question we were given the Maximum temperature in the system as

Tmax = 500°C

Minimum temperature in the system Tmin = 70°C

the Heat supplied to the boiler Qb = 240000 KJ/s

we use the temperature conversion factor from °C to K

given T(K) = T (°C) + 273

⇒ Tmax = 500 + 273 = 773 K

⇒ Tmin = 70 + 273 = 343 K

(a). we are to determine the maximum possible thermal efficiency;

(Πth)max = 1 - Tmin/Tmax

(Πth)max = 1 - 343/773 = 0.5562

(Πth)max = 55.62%

(b). to determine the maximum possible power output for the plant we have;

(Πth)max = Wmax/Qb

where Wmax rep the maximum power output

(Πth)max = 0.5562

Qb = 240000

∴ Wmax = 0.5562 × 240000 = 133505.6 Kw

Wmax = 133.5 MW

cheers i hope this helps

3 0

2 years ago

(This assignment could be done as a modification of the program in Programming Challenge 2.) Write a program char asks rhe user

JulijaS [17]

Answer:

Python

file=open("file_name",r) #Opening the file we are using

f1=file.readlines() #Read each line of the file and save it into f1 vector

for x in range(len(f1)): #walk through every line in vector f1 and print it

print(x+1, ".",f1[x]) """x+1 because the index begin in 0 so we add 1, ":" colon, f1[x] to take the x line"""

4 0

3 years ago