3.
If the reaction forms a new substance it's a chemical reaction.
Answer:
The claim is not reasonable
Explanation:
From the question we are told that
The power consumed is
The height of the pool's free surface is
The rate is
Given that the rate is 53 liters in 1 second , let say the 1 liter is equivalent to 1 kg so 50 liter = 50 kg
So the workdone by the pump is mathematically represented as
=>
=>
So what this value is telling us is that 14700 J of work is done in one second
and generally power is workdone per time thus the power consumed to move water at the given rate is 14.7 kW which is far greater than the power stated in the question so the claim is not reasonable
If the experiment had been repeated with frequencies 10 times lower than those in table 5.2, then Vc will increase 10 times to the values given in the table.
<h3 /><h3>What is frequency?</h3>
It is the number of oscillations per second of the sinusoidal wave.
Vc is the voltage across the capacitor and Xc is the capacitive reactance.
Xc = - 1/2πfC
where f is the frequency and C is the capacitance of the capacitor.
If the frequency is lowered, the potential difference will increase because frequency is inversely proportional to the voltage.
Thus, Vc will increase by lowering the frequency by 10 times.
Learn more about frequency.
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Answer:
The efficiency is define as the ratio between the work performed and the heat input at the higher temperature
Explanation:
The efficiency of the heat engine work done using working substance at higher temperature relates to the wasted energy released to the environment through the derived formula below:
Qin = quantity of heat from a working substance such steam or water used to drive electric generator at higher temperature for example
Qout = quantity of heat remaining in the working substance after the work has been done
Qin = Wout + Qout where Wout is the significant work that the higher temperature working substance has been used to do
Wout = Qin - Qout
efficiency = Wout / Qin = ( Qin - Qout) / Qin = Qin / Qin - Qout / Qin = 1 - (Qout / Qin) and
Carnot theorem relates the efficiency with the formula below:
eff( max) = 1 - ( Tc/Th) where Tc is the temperature of the cold reservoir where the working substance is poured and Th is the temperature of the working substance before it input into the thermal engine.