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2 years ago

Convert 5.7 cm to mm:

Physics

2 answers:

Irina-Kira [14]2 years ago

8 0

Answer:

57 mm

Explanation:

57 mm is equivalent to 5.7 cm

Marina86 [1]2 years ago

6 0

57 millimeters..........

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Three joules of work is needed to shift 10 C of charge from one place to another. The potential difference between the places is

dimaraw [331]

Answer:

The potential difference between the places is 0.3 V.

∴ 1st option i.e. 0.3V is the correct option.

Explanation:

Given

Work done W = 3J

Amount of Charge q = 10C

To determine

We need to determine the potential difference V between the places.

The potential difference between the two points can be determined using the formula

Potential Difference (V) = Work Done (W) / Amount of Charge (q)

$\:V\:=\:\frac{W}{q}$

substituting W = 3 and q = 10 in the formula

$V=\frac{3}{10}$

$V=0.3$ V

Therefore, the potential difference between the places is 0.3 V.

∴ 1st option i.e. 0.3V is the correct option.

4 0

2 years ago

The central star of a planetary nebula emits ultraviolet light with wavelength 104nm. This light passes through a diffraction gr

Gala2k [10]

Answer: 31.33 degrees

Explanation:

The diffraction angles $\theta_{n}$ when we have a slit divided into $n$ parts are obtained by the following equation:

$dsin\theta_{n}=n\lambda$ (1)

Where:

$d$ is the width of the slit

$\lambda$ is the wavelength of the light

$n$ is an integer different from zero.

Now, the first-order diffraction angle is given when $n=1$ , hence equation (1) becomes:

$dsin\theta_{1}=\lambda$ (2)

Now we have to find the value of $\theta_{1}$ :

$sin\theta_{1}=\frac{\lambda}{d}$

$\theta_{1}=arcsin(\frac{\lambda}{d})$ (3)

We know:

$\lambda=104nm=104(10)^{-9}m$

In addition we are told the diffraction grating has 5000 slits per mm, this means:

$d=\frac{1mm}{5000}=\frac{1(10)^{-3}m}{5000}$

Substituting the known values in (3):

$\theta_{1}=arcsin(\frac{104(10)^{-9}m}{\frac{1(10)^{-3}m}{5000}})$

$\theta_{1}=arcsin(0.52)$

<u>Finally:</u>

$\theta_{1}=31.33\º$ >>>This is the first-order diffraction angle

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2 years ago

Which event is an example of vaporization?

oksano4ka [1.4K]

B would be an example of vaporization (liquid to gas).

———————

A is an example of deposition (gas to solid); C is an example of condensation (gas to liquid); and D is an example of condensation, deposition, or freezing—depending on the type of cloud.

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2 years ago

Waves in the ocean are _____ traveling along the water

Mice21 [21]

The answer is energy.

Waves in the ocean are energy travelling along water.

Waves do not transport mass, they transport energy, this is the ability to perform work or exert force and distant points.

Although water seems to be travelling along with the wave, the molecules of water only move up and down; they do not travel along with the wave.

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2 years ago

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El peso de un cuerpo en la luna es?

8_murik_8 [283]

Answer:

1/6 del peso en la tierra.

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2 years ago