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lesya [120]
3 years ago
15

Grade 5 and 6 collect 12 times as many cans as grades 1 and 2. Grades 3 and 4 I collect 6683 cans, and that amount is 2389 cans

less than great 5 and 6. How many cans are collected by grades 5 and 6?
Mathematics
2 answers:
Bess [88]3 years ago
7 0

Answer: 9072

Step-by-step explanation:

It seems that the number of cans that grades 1 and 2 collect are irrelevant in the problem so you can basically ignore that. Grades 3 and 4 have 6683 cans which is 2389 cans less than grades 5 and 6 so that means grades 5 and 6 have 2389 cans more than 6683. Now you just add 6683 and 2389 to find the cans that grades 5 and 6 have.

6683 + 2389 =  9072

Grades 5 and 6 have 9072 cans

(there are a few typos is the problem and this is my first time answering so I'm really sorry if I got this wrong)

BlackZzzverrR [31]3 years ago
6 0

Answer:

9072

Step-by-step explanation:

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At a Noodles & Company restaurant, the probability that a customer will order a nonalcoholic beverage is .51.
satela [25.4K]

Answer:

P(x\geq 7)=0.1886

Step-by-step explanation:

The variable x, that said the number of customer that will order a nonalcoholic beverage in a sample of n customers follows a binomial distribution. Because we have n identical and independent events with a probability p of success and (1-p) of fail.

So, the probability that x customers will order a nonalcoholic beverage is:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}

Where n is the size of the sample and p is the probability that a customer order a nonalcoholic beverage, so replacing the values, we get:

P(x)=\frac{10!}{x!(10-x)!}*0.51^{x}*(1-0.51)^{10-x}

Now, the probability that at least 7 will order a nonalcoholic beverage is equal to:

P(x\geq 7)=P(7)+P(8)+P(9)+P(10)

Where:

P(7)=\frac{10!}{7!(10-7)!}*0.51^{7}*(1-0.51)^{10-7}=0.1267\\P(8)=\frac{10!}{8!(10-8)!}*0.51^{8}*(1-0.51)^{10-8}=0.0494\\P(9)=\frac{10!}{9!(10-9)!}*0.51^{9}*(1-0.51)^{10-9}=0.0114\\P(10)=\frac{10!}{10!(10-10)!}*0.51^{10}*(1-0.51)^{10-10}=0.0011

So, P(x\geq 7) is equal to:

P(x\geq 7)=0.1267+0.0494+0.0114+0.0011\\P(x\geq 7)=0.1886

Finally, the probability that in a sample of 10 customers, at least 7 will order a nonalcoholic beverage is equal to 0.1886

5 0
3 years ago
Write a real-world situation that could be modeled by the equation 500 + 250x = 300x
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8 0
3 years ago
A test is used to assess readiness for college. In a recent​ year, the mean test score was 20.3 and the standard deviation was 4
Vlada [557]

Answer:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can consider a value to be significantly low if we have that the z  score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is  higher tor equal to 2.

For this case we have the mean and the deviation given:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

6 0
3 years ago
Solve the equation : x^(2)+5=3(x^(2)-3)
Fittoniya [83]

Answer:

x = ± 2

Step-by-step explanation:

Given

x² + 5 = 3x² - 3 ( subtract x² + 5 from both sides )

0 = 2x² - 8 ( add 8 to both sides )

8 = 2x² ( divide both sides by 2 )

4 = x² ( take the square root of both sides )

x = ± \sqrt{4} = ± 2

6 0
3 years ago
Solve for x: 3-(2x-5)<-4(x+2)
trapecia [35]
3-(2x-5)=-4(x+2)

We simplify the equation to the form, which is simple to understand
3-(2x-5)=-4(x+2)

Remove unnecessary parentheses
3-2x+5=-4*(x+2)

Reorder the terms in parentheses
3-2x+5=+(-4x-8)

Remove unnecessary parentheses
+3-2x+5=-4x-8

We move all terms containing x to the left and all other terms to the right.
-2x+4x=-8-3-5

We simplify left and right side of the equation.
+2x=-16

We divide both sides of the equation by 2 to get x.
x=-8
6 0
3 years ago
Read 2 more answers
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