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alina1380 [7]
3 years ago
9

Find the LCM of 12, 16, and 20

Mathematics
2 answers:
laila [671]3 years ago
5 0
The LCM of 12,16, and 20 would be 240
Vilka [71]3 years ago
5 0
The answer is 25 hope this helps
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Is √1/9 greater less than or equal to 1/4​
victus00 [196]

Answer:

Greater:

\sqrt{1/9} > 1/4

Step-by-step explanation:

\sqrt{\frac{1}{9} } =\frac{\sqrt{1} }{\sqrt{3} } =\frac{1}{3}

1/3 is greater than 1/4

Hope this helps

7 0
2 years ago
Tyler picks 3/3 dozen apples. Olivia picks 5/6 dozen apples. Samantha picks 2/3 dozen apples. Who picks the least number of appl
Kitty [74]

For this case we have the following apple picking options, in dozens:

<em>Tyler:</em>

\frac {3} {3} = 1

Tyler picked up a dozen.

<em>Olivia:</em>

\frac {5} {6} = 0.833

Olivia collected 0.833 dozen apples.

<em>Samantha:</em>

\frac {2} {3} = 0.667

Samantha collected 0.667 dozens of apples.

Thus, it is observed that Samantha collected the least amount of apples.

ANswer:

Samantha

6 0
3 years ago
WILL GIVE 50 POINTS AND BRAINLIEST! <br><br>Write as a square of a binomial: 4.8xy+36y^2+0.16x^2
Bond [772]

Answer:

(6y+0.4x)^2

Step-by-step explanation:

i just did my rsm hw so if ur here from that it's the right answer :)

4 0
3 years ago
Read 2 more answers
Area of a pentagon with a radius of 8m
san4es73 [151]
Area = [radius^2 * 5 * sine (360/5)] / 2
area = [64 * 5 * 0.95106] / 2
area = <span> <span> <span> 152.1696 </span> </span> </span>





4 0
3 years ago
The domain of startfraction f over g endfraction f g consists of numbers x for which g left parenthesis x right parenthesisg(x)
Misha Larkins [42]

The domain of f/g consists of numbers x for which g(x) cannot equal 0 that are in the domains of both f and g.

 

Let’s take this equation as an example:

If f(x) = 3x - 5 and g(x) = square root of x-5, what is the domain of (f/g)x. 


For x to be in the domain of (f/g)(x), it must be in the domain of f and in the domain of g since (f/g)(x) = f(x)/g(x). We also need to ensure that g(x) is not zero since f(x) is divided by g(x). Therefore, there are 3 conditions.

 

x must be in the domain of f: f(x) = 3x -5 are in the domain of x and all real numbers x.

x must be in the domain of g: g(x) = √(x - 5) so x - 5 ≥ 0 so x ≥ 5.

g(x) can not be 0: g(x) = √(x - 5) and √(x - 5) = 0 gives x = 5 so x ≠ 5.

 

Hence to x x ≥ 5 and x ≠ 5 so the domain of (f/g)(x) is all x satisfying x > 5.

 

Thus, satisfying <span>satisfy all three conditions, x x ≥ 5 and x ≠ 5 so the domain of (f/g)(x) is all x satisfying x > 5.</span>

5 0
3 years ago
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