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kykrilka [37]
3 years ago
8

What is the domain of the function y= square root of X plus 4​

Mathematics
1 answer:
kumpel [21]3 years ago
5 0

Answer: all real numbers

Step-by-step explanation:

the domain for any function is always, all real numbers or in other words, negative infinity to positive infinity.

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Find the<br> equation of the circle with center at (3, -2) and radius of 3.
kvasek [131]
(x-3) *squared* + (y + 2) *squared* = 6
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Use the functions f(x)=2x and g(x)=x^2+1 to find the value of each expression
Alinara [238K]

Answer:

1.  20

2. 23

3. 6

Step-by-step explanation:

We have that:

f(x) = 2x

g(x) = x² + 1

f(g(x)) is the composite function of f and g. So

f(g(x)) = f(x²-1) = 2(x²+1) = 2x² + 2

1. f(g(3))

f(g(x)) = 2x² - 2 = 2(3)² + 2 = 18 + 2 = 20

2. f(3)+g(4)

f(3) = 2(3) = 6

g(4) = 4² + 1 = 17

f(3) + g(4) = 6 + 17 = 23

3. f(5) - 2g(1)​

f(5) = 2(5) = 10

g(1) = (1)² + 1 = 2

f(5) - 2g(1) = 10 - 2*2 = 10 - 4 = 6

6 0
3 years ago
Carla figures she spends 21% of her income on food. which fraction is a good estimate for 21%
blsea [12.9K]
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Because that’s what I think it is
7 0
3 years ago
What is the value of the expression 2(3/4 - 1) + 0.35
skelet666 [1.2K]

Answer:

-.15

Step-by-step explanation:

you first do whats in the parantheses (3/4 - 1) which equals -.25, then multiply by 2 which gives you -.5, now add .35 and your total is -.15

5 0
3 years ago
Read 2 more answers
Please Help It Is Past Due!
Step2247 [10]

Explanation:

First we consider ΔABC and ΔBCD,

∠C=∠C  (common)

∠B=∠D=90\textdegree

So, ΔABC ≈ ΔBCD (By AA similarity rule )

So by taking corresponding sides in ratios we get

\frac{AB}{BD}=\frac{AC}{BC}=\frac{BC}{CD}      

Now

AC.CD=BC.BC\\BC^{2} =AC.CD              -------- Eqn (1)

Similarly,

We consider ΔABD and ΔABC

∠A=∠A (Commom)

∠B=∠D=90\textdegree

So,

ΔABD ≈ ΔABC (By AA similarity rule )

So by taking corresponding sides in ratios we get

\frac{BC}{BD}=\frac{AC}{AB}=\frac{AB}{AD}  

Now,

AB.AB=AC.AD\\AB^{2} =AC.AD              --------Eqn (2)

By Adding both the equation we get

AB^2+BC^2=AC.CD+AC.AD\\AB^2+BC^2=AC(CD+AD)\\AB^2+BC^2=AC.AC\\AB^2+BC^2=AC^2

Hence, we proved the pythagorean theorem by using similarity of triangle.



3 0
3 years ago
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