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LuckyWell [14K]
3 years ago
12

Help me please please someone help me please

Chemistry
2 answers:
poizon [28]3 years ago
6 0

Under Control

Independent Variable

Dependent Variable

Constant Through It All

love history [14]3 years ago
4 0

Some characteristics include: a question, hypothesis, procedure, results, and conclusion, data.

-I haven't done science in while, but that should be it. BTW it is not in order

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Calculate δs∘rxn for the reaction2no(g) o2(g)→2no2(g)express your answer to one decimal place and include the appropriate units
Anna35 [415]

The δs∘rxn  for the reaction 2NO(g) + O_{2} → 2NO_{2} (g) will be -146 J/K.

Entropy would be a measurable physical characteristic and a scientific notion that is frequently connected to a condition of disorder, unpredictability, or uncertainty.

Entropy would be a measurement of the system's unpredictability or disorder. The entropy increases as randomness do. It has broad properties as well as a state function. It has the unit JK^{-1} mol^{-1}.

Entropy of the reaction can be calculated by the reaction.

ΔS^{0} rxn = 2 mol × S^{0} (NO_{2} (g) - 2 mol × S^{0} NO (g) - 1 mol × S^{0} (O_{2} )

ΔS^{0} rxn  = 2 mol × 240 J/mol.K - 2 mol × 210 J/mol.K-1 mol  ×205.2 J/mol.K

ΔS^{0} rxn  = -146.8 J/K

Therefore, the δs∘rxn  for the reaction 2NO(g) + O_{2} → 2NO_{2} (g) will be -146 J/K.

To know more about reaction

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4 0
1 year ago
Which formula for sulfuric acid is written correctly to show one sulfur atom, two hydrogen atoms, and four oxygen atoms?
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3 years ago
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Answer:

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In this experiment we will be using a 0.05 M solution of HCl to determine the concentration of hydroxide (OH-) in a saturated so
gulaghasi [49]

<u>Answer:</u> The moles of hydroxide ions present in the sample is 0.0008 moles

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl.

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.05M\\V_1=16mL\\n_2=2\\M_2=?M\\V_2=36.0mL

Putting values in above equation, we get:

1\times 0.05\times 16=2\times M_2\times 36\\\\M_2=\frac{1\times 0.05\times 16}{2\times 36}=0.011M

To calculate the moles of hydroxide ions, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

Molarity of solution = 0.011 M

Volume of solution = 36.0 mL

Putting values in above equation, we get:

0.011=\frac{\text{Moles of }Ca(OH)_2\times 1000}{36}\\\\\text{Moles of }Ca(OH)_2=\frac{0.011\times 36}{1000}=0.0004mol

1 mole of calcium hydroxide produces 1 mole of calcium ions and 2 moles of hydroxide ions.

Moles of hydroxide ions = (0.0004 × 2) = 0.0008 moles

Hence, the moles of hydroxide ions present in the sample is 0.0008 moles

8 0
2 years ago
A reaction of 17.0 g of ammonia with 26.6 g of chlorine gas
Elena-2011 [213]

Answer: if doing it on ck-12 the answer is 40.1

Explanation:

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