Answer: Option (C) is the correct answer.
Explanation:
Chemical formula of a secondary amide is R'-CONH-R, where R and R' can be same of different alkyl or aryl groups. Here, the hydrogen atom of amide is attached to more electronegative oxygen atom of the C=O group.
Therefore, the hydrogen atom will be more strongly held by the electronegative oxygen atom. As a result, there will be strongly hydrogen bonded in the liquid phase of secondary amide.
Whereas chemical formula of nitriles is RCN, ester is RCOOR' and acid chlorides are RCOCl. As no hydrogen bonding occurs in any of these compounds because hydrogen atom is not being attached to an electronegative atom.
Thus, we can conclude that secondary amides are strongly hydrogen bonded in the liquid phase.
Answer:
1.78 atm
Explanation:
From the question given above, the following data were obtained:
Mass of Cl = 355 g
Molecular weight of Cl = 70.9 g/mol
Volume (V) = 70.0 L
Temperature (T) = 30 °C
Pressure (P) =?
Next, we shall determine the number of mole in 355 g of chlorine (Cl). This can be obtained as follow:
Mass of Cl = 355 g
Molecular weight of Cl = 70.9 g/mol
Mole of Cl =.?
Mole = mass /molecular weight
Mole of Cl = 355 /70.9
Mole of Cl = 5 moles
Next, we shall convert 30 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Temperature (T) = 30 °C
Temperature (T) = 30 °C + 273 = 303 K
Finally, we shall determine the pressure of the gas as illustrated below:
Volume (V) = 70.0 L
Number of mole (n) = 5 moles
Temperature (T) = 303 K
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =?
PV = nRT
P × 70 = 5 × 0.0821 × 303
P × 70 = 124.3815
Divide both side by 70
P = 124.3815 / 70
P = 1.78 atm
Therefore, the pressure of the gas is 1.78 atm
Answer:
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