Answer:
T°fussion of solution is -18°C
Explanation:
We have to involve two colligative properties to solve this. Let's imagine that the solute is non electrolytic, so i = 1
First of all, we apply boiling point elevation
ΔT = Kb . m . i
ΔT = Boiling T° of solution - Boiling T° of pure solvent
Kb = ebuliloscopic constant
105°C - 100° = 0.512 °C kg/mol . m . 1
5°C / 0.512 °C mol/kg = m
9.7 mol/kg = m
Now that we have the molality we can apply, the Freezing point depression.
ΔT = Kf . m . i
Kf = cryoscopic constant
0° - (T°fussion of solution) = 1.86 °C/m . 9.76 m . 1
- (1.86°C /m . 9.7 m) = T°fussion of solution
- 18°C = T°fussion of solution
Answer:
Observation
-I smell onions
-My dog weighs 45 pounds
-It is 85 degrees outside today
Predictions
-My dog will bark at the vacuum cleaner
although he has never seen it before
-My mother is going to cook spaghetti for
supper next Tuesday
-It will be a long, hot summer
Explanation:
Answer:
Step 3
Explanation:
I am back sorry it took me so long, I believe its Step 3 because that's were you chose your strategy, you use it in Step 4, but if its not Step 3 its Step 4
1. identifying
problem solving step: 1)__ the problem is most difficult: not in habit of asking what the problem really is; in the habit of reacting or giving up
2. representing
problem solving step: 2) __ the problem: abstract or external representation
3. strategy
problem solving step: 3) selecting an appropriate __; trial and error vs means-ends analysis
4. implementing
problem solving step: 4) __ the strategy; dependent on previous steps
